我想要一个用于验证管理员的代码,然后如果成功,管理员必须输入文件名,以便从数据库中检索文件ID等文件内容
答案 0 :(得分:0)
THE HTML CODE:
<html>
<head>
<title>Login page</title>
<style>
body{ background-image: url("wall0003.png");
width: 200%;
height: 200%;
background-position: top;
background-repeat: no-repeat;}
</style>
</head>
<body text="black" align="left">
<form action="connectivity.php" onsubmit="post">
<br/>
<br/> <br/>
<br/> <br/> <br/> <br/><br/><br/><br/><br/><br/><br/><br/><br/><br/><br/>
User
<input type="text" name="userid"/> <br/><br/>
Pswd<input type="password" name="pswrd"/> <br/><br/>
<input type="submit" value="Login" name="Login"/>
<input type="reset" value="Cancel"/>
</form>
<script language="javascript">
function check(form) {
/*function to check userid & password
the following code checkes whether the entered userid and password are matching*/
if(form.userid.value == "myuserid" && form.pswrd.value == "mypswrd")
{
window.open('target.html') //opens the target page while Id & password matches
}
else {
alert("Error Password or Username") // displays error message
}
}
</script>
</body>
</html>
PHP CODE:
<?php
define('DB_HOST', 'localhost');
define('DB_NAME', 'practice');
define('DB_USER','root');
define('DB_PASSWORD','admin');
$con=mysql_connect(DB_HOST,DB_USER,DB_PASSWORD) or die("Failed to connect to MySQL: " . mysql_error()); //connect to mysql
$db=mysql_select_db(DB_NAME,$con) or die("Failed to connect to MySQL: " . mysql_error()); //select a mysql database
/*
$ID = $_POST['user'];
$Password = $_POST['pass'];
*/
function SignIn()
{
session_start(); //starting the session for user profile page
if(!empty($_POST['user'])) //checking the 'user' name which is from login.html...is it empty or has some text?
{
$query = mysql_query("SELECT * FROM UserName where userName = '$_POST[user]' AND pass = '$_POST[pass]'") or die(mysql_error());//send mysql query to the database
$row = mysql_fetch_array($query) or die(mysql_error()); //fetch a row result
if(!empty($row['userName']) AND !empty($row['pass']))
{
$_SESSION['userName'] = $row['pass'];
echo "SUCCESSFULLY LOGIN TO USER PROFILE PAGE...";
}
else
{
echo "SORRY... YOU ENTERD WRONG ID AND PASSWORD... PLEASE RETRY...";
}
}
}
if(isset($_POST['submit']))
{
SignIn();
}
?>