Question

新来的。请查看我的文档字符串，看看我尝试做什么：

def count(data):
    """ (list of list of str) -> list of int

    Return the numbers of occurrences of strings that end in digits 0, 1, or 2
    for each string.

    >>> data = [['N', 'OW1'], ['Y', 'EH1', 'S'], ['AW1', 'OW1']]
    >>> count(data)
    [1, 1, 2]
    """

    num_list = []
    num = 0

    for sublist in phonemes:
        for item in sublist:
            if item[-1].isdigit():
                num += 1
        num_list.append(num)
    return num_list

我不知道如何为每个data sublist创建一个号码。这甚至是正确的方法吗？任何帮助都会很棒。

Answer 1

试试这个。

def count(data):
    """ (list of list of str) -> list of int

    Return the numbers of occurrences of strings that end in digits 0, 1, or 2
    for each string.

    >>> data = [['N', 'OW1'], ['Y', 'EH1', 'S'], ['AW1', 'OW1']]
    >>> count(data)
    [1, 1, 2]
    """

    return [ len([item for item  in sublist if item[-1].isdigit()]) for sublist in data]

Answer 2

通过list_comprehension。

>>> data = [['N', 'OW1'], ['Y', 'EH1', 'S'], ['AW1', 'OW1']]
>>> [len([j for j in i if j[-1] in "012"]) for i in data]
[1, 1, 2]

Answer 3

我的解决方案：

def count(data):
    nums = []
    for sub in data:
        occur = 0
        for i in sub:
            if i.endswith(('0', '1', '2')):
                occur += 1
        nums.append(occur)
    return nums

Answer 4

我认为你有正确的想法，但在完成子列表后你没有将num重置为0。你现在正在做的是计算所有子列表中的总数0,1,2。你想要的是每个子列表的计数。

在完成整个子列表后，您还必须附加num。所以你需要将它放在内部for循环体中。

修：

def count(data):
    """ (list of list of str) -> list of int

    Return the numbers of occurrences of strings that end in digits 0, 1, or 2
    for each string.

    >>> data = [['N', 'OW1'], ['Y', 'EH1', 'S'], ['AW1', 'OW1']]
    >>> count(data)
    [1, 1, 2]
    """

    num_list = []
    num = 0

    for sublist in data:
        for item in sublist:
            if item[-1] in "012":
                num += 1

        # item in sublist body is over
        # num is now total occurrences of 0,1,2 in sublist
        num_list.append(num)
        num = 0
    return num_list 

print count([['N', 'OW1'], ['Y', 'EH1', 'S'], ['AW1', 'OW1']])

Answer 5

>>> data = [['N', 'OW1'], ['Y', 'EH1', 'S'], ['AW1', 'OW1']]
>>> the_lengths = [i for i in map(int, [len([i for i in thelist if i[-1].isdigit()]) for thelist in data])]
>>> the_lengths
[1, 1, 2]

计算字符串列表中的数字并将它们作为整数列表返回

5 个答案: