Question

我可以通过使用子串断开字符串来实现这一点，但应该有一些方法来解析特定格式的字符串并获得所需的值。

如果还有其他简单而优雅的方法，请帮助我。

[更新] 这就是我使用子串的方式：

NSRange ptRange = [timeString rangeOfString:@"T"];
NSRange hRange = [timeString rangeOfString:@"H"];
NSRange mRange = [timeString rangeOfString:@"M"];

NSString *hours = nil;
if (hRange.location != NSNotFound) {
    hours = [timeString substringWithRange:NSMakeRange(ptRange.location+ptRange.length, hRange.location-(ptRange.location+ptRange.length))];
}
else {
    hRange = ptRange;
}

NSString *minutes = nil;
if (mRange.location != NSNotFound) {
    minutes = [timeString substringWithRange:NSMakeRange(hRange.location+hRange.length, mRange.location-(hRange.location+hRange.length))];
}
NSDateFormatter *df = [[NSDateFormatter alloc] init];
[df setDateFormat:@"HH:mm"];
NSDate*date = [df dateFromString:[NSString stringWithFormat:@"%d:%d",hours.integerValue,minutes.integerValue]];

Answer 1

截至目前，我的实施是这个问题的答案

NSRange ptRange = [timeString rangeOfString:@"T"];
NSRange hRange = [timeString rangeOfString:@"H"];
NSRange mRange = [timeString rangeOfString:@"M"];

NSString *hours = nil;
if (hRange.location != NSNotFound) {
    hours = [timeString substringWithRange:NSMakeRange(ptRange.location+ptRange.length, hRange.location-(ptRange.location+ptRange.length))];
}
else {
    hRange = ptRange;
}

NSString *minutes = nil;
if (mRange.location != NSNotFound) {
    minutes = [timeString substringWithRange:NSMakeRange(hRange.location+hRange.length, mRange.location-(hRange.location+hRange.length))];
}
NSDateFormatter *df = [[NSDateFormatter alloc] init];
[df setDateFormat:@"HH:mm"];
NSDate*date = [df dateFromString:[NSString stringWithFormat:@"%d:%d",hours.integerValue,minutes.integerValue]];

解析时间PT ## H ## M到NSDate

1 个答案: