Question

当我运行它时它告诉我：关键字'SELECT'附近的语法不正确。但我需要将其传递给剩下的脚本 - 这些值用于搜索 - 这是唯一需要进行抛光的块修改

 BEGIN

DECLARE @ResultsTable TABLE (ColumnName nvarchar(200), ColumnValue nvarchar(100))

DECLARE @ColumnName nvarchar(128), 
        @SearchStr2 nvarchar(110),
        @TableName nvarchar(256), 
        @TableName2 nvarchar(256)

DECLARE @PolicyPrefix nvarchar(5), 
        @PolicyID nvarchar(10), 
        @PolicyEffDate date, 
        @Policy nvarchar(10),  --needless ,
SET @TableName = ' '

SET @PolicyPrefix = SELECT SUBSTRING(Policy, 1, 5) 
                    FROM [dbo].[DWXP050] 
                WHERE intcov LIKE '%epl%' --'CMPMO' ------notices it only the policy letter part from the search result

SET @PolicyID = SELECT SUBSTRING(Policy,6,len(Policy)-5) 
                FROM [dbo].[DWXP050] 
             WHERE intcov LIKE '%epl%'  ---'08929' ------notices it only the policy number part from the search result

SET @PolicyEffDate = SELECT cast(cast(EFFDTE as varchar)as date) 
                     FROM [dbo].[DWXP050] 
                 WHERE intcov LIKE '%epl%' ----'2009-11-01' ------notices it has dashes from the search result

Answer 1

尝试：

SELECT @PolicyPrefix = SUBSTRING(Policy, 1, 5) FROM [dbo].[DWXP050] WHERE intcov LIKE '%epl%' --'CMPMO' ------notices it only the policy letter part from the search result

SELECT @PolicyID = SUBSTRING(Policy, 6) FROM [dbo].[DWXP050] WHERE intcov LIKE '%epl%'---'08929' ------notices it only the policy number part from the search result

SELECT @PolicyEffDate = cast(cast(EFFDTE as varchar)as date) FROM [dbo].[DWXP050] WHERE intcov LIKE '%epl%' ----'2009-11-01' ------notices it has dashes from the search result

Answer 2

SET @PolicyID = SELECT SUBSTRING(Policy, 6) FROM [dbo].[DWXP050] WHERE intcov LIKE '%epl%'---'08929' ------notices it only the policy number part from the search result

您尚未在此行中为子字符串函数添加第三个参数。添加它

Answer 3

将select语句放在（）中，如 -

SET @PolicyPrefix = (SELECT SUBSTRING(Policy, 1, 5) FROM [dbo].[DWXP050] WHERE intcov LIKE '%epl%')

在@policy nvarchar（10）之后你有了Needless（，）

Answer 4

'/这些是我所做的改变，这是对我有用的答案。谢谢大家./'

  BEGIN

    DECLARE @ResultsTable TABLE ( ColumnName  nvarchar(200)
    ,                             ColumnValue nvarchar(100) )

    DECLARE @ColumnName nvarchar(128)
    ,       @SearchStr2 nvarchar(110)
    ,       @TableName  nvarchar(256)
    ,       @TableName2 nvarchar(256)

    DECLARE @PolicyPrefix  nvarchar(5)
    ,       @PolicyID      nvarchar(10)
    ,       @PolicyEffDate date
    ,       @Policy        nvarchar(13)

    --SET @SearchStr2 = QUOTENAME('%' + @SearchStr + '%','''')

    SET @TableName = ' '

    --These values are used to search

    SET @PolicyPrefix = (SELECT TOP 1 SUBSTRING(Policy, 1, 5)
    FROM [dbo].[DWXP050]
    WHERE intcov LIKE '%epl%') --'CMPMO' ------notices it only the policy letter part from the search result

    SET @PolicyID = (SELECT TOP 1 SUBSTRING(Policy,6,len(Policy)-5)
    FROM [dbo].[DWXP050]
    WHERE intcov LIKE '%epl%')---'08929' ------notices it only the policy number part from the search result

    SET @PolicyEffDate = (SELECT TOP 1 cast(cast(EFFDTE as varchar)as date)
    FROM [dbo].[DWXP050]
    WHERE intcov LIKE '%epl%') ----'2009-11-01' ------notices it has dashes from the search result

    SET @SearchStr2 = (SELECT [SystemAssignId]
    FROM dbo.[CoPolicyPointer]

    WHERE [PolicyPrefixCd] = @PolicyPrefix

        AND [PolicyId] = @PolicyID

        AND [PolicyEffDt] = @PolicyEffDate)

    WHILE (@TableName IS NOT NULL)
    BEGIN

        SET @ColumnName = QUOTENAME('SystemAssignId')

        SET @TableName = (

        SELECT MIN(QUOTENAME(TABLE_NAME))

        FROM INFORMATION_SCHEMA.TABLES

        WHERE TABLE_TYPE = 'BASE TABLE'

            AND QUOTENAME(TABLE_NAME) > @TableName

        )

        SET @TableName2 = 'dbo.' + @TableName

        IF @ColumnName IS NOT NULL
        BEGIN

            INSERT INTO @ResultsTable

            EXEC(

            'SELECT ''' + @TableName + ''', LEFT(' + @ColumnName + ', 100)

FROM ' + @TableName2 + ' (NOLOCK) ' +

            ' WHERE ' + @ColumnName + ' LIKE ''' + @SearchStr2 + ''''

            )

        END

    END

    SELECT DISTINCT ColumnName
    ,               ColumnValue
    FROM @ResultsTable

END

如何使用子字符串返回set变量？

4 个答案: