SQL到CodeIgniter数组缺少数据问题

时间:2010-05-30 03:35:49

标签: php sql mysql arrays codeigniter

$query = $this->db->query("SELECT t1.numberofbets, t1.profit, t2.seven_profit, t3.28profit, user.user_id, username, password, email, balance, user.date_added, activation_code, activated FROM user LEFT JOIN (SELECT user_id, SUM(amount_won) AS profit, count(tip_id) AS numberofbets FROM tip GROUP BY user_id) as t1 ON user.user_id = t1.user_id LEFT JOIN (SELECT user_id, SUM(amount_won) AS seven_profit FROM tip WHERE date_settled > '$seven_daystime' GROUP BY user_id) as t2 ON user.user_id = t2.user_id LEFT JOIN (SELECT user_id, SUM(amount_won) AS 28profit FROM tip WHERE date_settled > '$twoeight_daystime' GROUP BY user_id) as t3 ON user.user_id = t3.user_id where activated = 1 GROUP BY user.user_id ORDER BY user.date_added DESC");

return $query->result_array();

查询在phpMyAdmin中正常运行并返回完整的结果(在附加的图像中)。但是,在CodeIgniter中打印数组,它没有一个字段的值,seven_profit,它在phpMyAdmin中运行的SQL查询中,只是这一个字段中的差异,从sql到php数组...我只是可以'为什么,在打印数组时,为什么一个字段(其值应为26)不包含任何内容?有任何想法吗?我改变了字段名称,从一个数字开始,试图修复它,但没有区别。

我知道这很复杂,看起来很糟糕,任何帮助或只是遇到类似事情的人都会很高兴知道,谢谢。

萨姆


编辑:查询格式更多:

$query = $this->db->query("
  SELECT
    t1.numberofbets, t1.profit, t2.seven_profit, t3.28profit,
    user.user_id, username, password, email,
    balance, user.date_added, activation_code, activated
  FROM
    user
  LEFT JOIN
    (
      SELECT
        user_id,
        SUM(amount_won) AS profit,
        count(tip_id) AS numberofbets
      FROM
        tip
      GROUP BY
        user_id
    ) as t1
  ON
    user.user_id = t1.user_id
  LEFT JOIN
    (
      SELECT
        user_id,
        SUM(amount_won) AS seven_profit
      FROM
        tip
      WHERE
        date_settled > '$seven_daystime'
      GROUP BY
        user_id
    ) as t2
  ON
    user.user_id = t2.user_id
  LEFT JOIN
    (
      SELECT
        user_id,
        SUM(amount_won) AS 28profit
      FROM
        tip
      WHERE
        date_settled > '$twoeight_daystime'
      GROUP BY
        user_id
    ) as t3
  ON
    user.user_id = t3.user_id
  WHERE
    activated = 1
  GROUP BY
    user.user_id
  ORDER BY
    user.date_added DESC
");

1 个答案:

答案 0 :(得分:0)

好的问题是SQL查询包含PHP变量,这些变量必须只被视为0或者没有给出错误的东西,因此它会在seven_profit列中显示一个值。

当在CodeIgniter中运行查询时,它使用$seven_daystime变量的正确值,因此当数据放入数组时结果会有所不同。

/责备疲倦