Question

我不会you’ll缩减为you ll（不是youll）。这就是我正在做的事情：

>>> clean = "you'll"
>>> import string
>>> clean = filter(lambda x: x in string.printable, clean)
>>> print clean
you'll

>>> clean = "you’ll" 
>>> clean = filter(lambda x: x in string.printable, clean)
>>> print clean
youll

这就是我的尝试：

>>> clean = "you'll"
>>> clean =clean.replace('\'',' ')
>>> print clean
you ll
>>> clean = "you’ll"
>>> clean =clean.replace('’',' ')
>>> print clean
you ll

这很好用，但当我把它放在我的脚本中时：

SyntaxError: Non-ASCII character '\xe2' in file sc.py on line 177, but no encoding declared; see http://www.python.org/peps/pep-0263.html for details

所以，我添加到我的脚本的顶部：

# -*- coding: utf-8 -*-

但是得到

clean =clean.replace('’',' ')
UnicodeDecodeError: 'ascii' codec can't decode byte 0xe2 in position 0: ordinal not in range(128)

我有点想法。

Answer 1

这可能不是最佳答案，但一个简单的解决方案就是处理异常：

clean2 = ""
for ch in clean:
    try:
        clean2 += " " if ch == "'" else clean2 += ch
    except UnicodeDecodeError:
        clean2 += 'vs.'

Answer 2

您需要decode字符串

# -*- coding: utf-8 -*- 
clean = "you’ll".decode('utf-8')
clean = clean.replace('’'.decode('utf-8'),' ')
print clean

这print s

you ll

这是预期的

Answer 3

您可以使用replace()替换撇号，如下所示：

print "you'll".replace("'", " ")

打印you ll

替换Python中的非ASCII字符：例如，'vs'

3 个答案: