我遇到了我的User对象的Jackson序列化问题。 有一些私人领域有getter和setter。当我做这样的事情时,一切正常:
public String json() {
MyUser user = new MyUser();
user.setUsername("myName");
return mapper.writeValueAsString(user); // Valid JSON
}
但我想用Spring Framework自动装配User对象:
@Autowired
private MyUser user;
public String json() {
System.out.println(user.getUsername()); // Property set before and it works
return mapper.writeValueAsString(user); // Error
}
这不起作用。我有一个错误:
com.fasterxml.jackson.databind.JsonMappingException: No serializer found for class org.apache.juli.OneLineFormatter and no properties discovered to create BeanSerializer (to avoid exception, disable SerializationFeature.FAIL_ON_EMPTY_BEANS) ) (through reference chain: com.piggymetrics.classes.PiggyUser$$EnhancerBySpringCGLIB$$5f23855e["targetSource"]->org.springframework.aop.target.SimpleBeanTargetSource["beanFactory"]->org.springframework.beans.factory.support.DefaultListableBeanFactory["parentBeanFactory"]->org.springframework.beans.factory.support.DefaultListableBeanFactory["beanClassLoader"]->org.apache.catalina.loader.WebappClassLoader["resources"]->org.apache.catalina.webresources.StandardRoot["context"]->org.apache.catalina.core.StandardContext["logger"]->org.apache.juli.logging.DirectJDKLog["logger"]->java.util.logging.Logger["parent"]->java.util.logging.Logger["handlers"]->org.apache.juli.AsyncFileHandler["formatter"])
at com.fasterxml.jackson.databind.ser.impl.UnknownSerializer.failForEmpty(UnknownSerializer.java:59)
at com.fasterxml.jackson.databind.ser.impl.UnknownSerializer.serialize(UnknownSerializer.java:26)
当我试图忽略这些未知错误时
mapper.disable(SerializationFeature.FAIL_ON_EMPTY_BEANS);
我得到了无限递归:
com.fasterxml.jackson.databind.JsonMappingException: Infinite recursion (StackOverflowError) (through reference chain: org.apache.catalina.core.StandardEngineValve["container"]->org.apache.catalina.core.StandardEngine["pipeline"]->org.apache.catalina.core.StandardPipeline["basic"]->org.apache.catalina.core.StandardEngineValve["container"]
...
看起来Spring在自动装配的MyUser实例上做错了,所以杰克逊无法将其序列化。
有没有办法解决它?
更新
MyUser类非常简单:
package com.metrics.classes;
import com.metrics.classes.interfaces.User;
import org.springframework.context.annotation.Scope;
import org.springframework.context.annotation.ScopedProxyMode;
import org.springframework.stereotype.Component;
@Component
@Scope(value = "session", proxyMode = ScopedProxyMode.TARGET_CLASS)
public class MyUser implements User {
private String username;
public String getUsername() {
return username;
}
public void setUsername(String username) {
this.username = username;
}
}
答案 0 :(得分:2)
由于您使用MyUser
作为Spring托管bean,Spring将您的对象包装到代理中 - 因此当您调用mapper.writeValueAsString(user);
时,您实际上是将代理作为参数传递。所述代理包含一些属性,映射器无法序列化。
您可以尝试在序列化之前应用过滤器,以仅包含您需要的属性:
ObjectMapper mapper = new ObjectMapper();
SimpleFilterProvider simpleFilterProvider = new SimpleFilterProvider()
.addFilter("myUser", simpleBeanPropertyFilter.filterOutAllExcept("username"));
mapper.setFilters(filterProvider);
return mapper.writeValueAsString(user);
答案 1 :(得分:1)
UnknownSerializer
类中抛出此异常。以下是引发异常的确切代码:
throw new JsonMappingException("No serializer found for class "+value.getClass().getName()
+" and no properties discovered to create BeanSerializer
(to avoid exception, disable SerializationFeature.FAIL_ON_EMPTY_BEANS) )");
错误消息附加了无法序列化的类的名称。在您的情况下,根据错误消息,问题出在org.apache.juli.OneLineFormatter
类。因此,MyUser
类没有问题。
现在出现这个错误的原因,在序列化一个私有所有字段的实体时会抛出它。在org.apache.juli.OneLineFormatter
类中,所有字段都是私有的,没有任何公共getter和setter方法。