Question

将php脚本移植到golang时遇到问题。

golang中是否有类似于php的方法：

$processRefList = $faceContainer->getElementsByTagName('processRef');

有一个xml文件，其中包含大量名为processRef的嵌套元素。

所以我需要收集所有这些元素而不处理嵌套结构树。

这是xml的一个示例部分：

<face>
<processes>
    <process group="1" type="regular"/>
    <process group="2" type="spotUV" state="off"/>
</processes>
<assets>...</assets>
<groups>
    <group id="1">
        <assetRefs>
            <imageRef ref="1" x="0" y="0" id="8">
                <processRefs>
                    <!-- This applies spotUV to this asset and removes the regular process. -->
                    <processRef ref="1" state="off"/>
                    <processRef ref="2" state="on"/>
                </processRefs>
            </imageRef>
            <textRef ref="1" x="161" y="41" id="7"/>
            <textRef ref="2" x="160" y="55" id="6">
                <processRefs>
                    <!-- This applies spotUV to this asset and also leaves regular process applied. -->
                    <processRef ref="2" state="on"/>
                </processRefs>
            </textRef>
        </assetRefs>
    </group>
    <group id="2">...</group>
</groups>

Answer 1

我写了一个可以处理这个用例的包：

package main

import (
   "github.com/89z/mech"
   "os"
)

func main() {
   f, err := os.Open("file.xml")
   if err != nil {
      panic(err)
   }
   defer f.Close()
   doc, err := mech.Parse(f)
   if err != nil {
      panic(err)
   }
   ref := doc.ByTag("processRef")
   for ref.Scan() {
      state := ref.Attr("state")
      println(state)
   }
}

结果：

off
on
on

https://pkg.go.dev/github.com/89z/mech

Answer 2

////store all xml data in var response
type XMLQuery struct {
Loc string `xml:",chardata"`
}
var l XMLQuery
decoder := xml.NewDecoder(strings.NewReader(string(response))) //store 
all xml data in var response
for {

token, _ := decoder.Token()

if token == nil {
  break
}

switch Element := token.(type) {
case xml.StartElement:
  if Element.Name.Local == "processRef" {
    fmt.Println("Element name is : ", Element.Name.Local)

    err := decoder.DecodeElement(&l, &Element)
    if err != nil {
      fmt.Println(err)
    }

    attrVal :=l.Loc
    fmt.Println("Title: ", attrVal)

}}}

Answer 3

试试这个

$extractvar = new DOMDocument();
$extractvar ->load("yourfile");

$itemextract= $extractvar ->getElementsByTagName("faceContainerRefs");

foreach( $itemextract as $value )
{
$var1= $value->getElementsByTagName("faceContainerRef ");
$var= $var1->item(0)->nodeValue;
}

在golang中收集具有给定名称的所有xml结构

3 个答案: