我有爱因斯坦谜语猫头鹰填充的OWLIM存储库。 Link1 - Link2。是否可以使用sparql从OWLIM查询推断的知识?要获得与Protege中单个选项卡相同的结果?
SPARQL:
PREFIX riddle: <http://www.iis.nsk.su/persons/ponom/ontologies/einsteins_riddle_en.owl#>
SELECT DISTINCT ?kto ?co
WHERE {
?kto riddle:drinks ?co .
?kto a owl:Thing .
?co a owl:Thing .
Protege和OWLIM具有相同的结果,只有明确的知识。
co kto
---------------------------------------------
http://www.iis.nsk.su/persons/ponom/ontologies/einsteins_riddle_en.owl#tea http://www.iis.nsk.su/persons/ponom/ontologies/einsteins_riddle_en.owl#Ukrainian
但是(根据我的信息)在Protege中,SPARQL查询仅适用于现有知识和OWLIM构建存储库,包含现有和推断的三元组。所以我也期望推断出三元组。
P.S .: 查询以获得推断的三元组计数(OWLIM):
SELECT (COUNT(*) as ?count)
FROM <http://www.ontotext.com/implicit>
WHERE {
?s ?p ?o .
}
返回0.
** ** ** 编辑: ** ** **
我的配置:
#
# Sesame configuration template for a owlim repository
#
@prefix rdfs: <http://www.w3.org/2000/01/rdf-schema#>.
@prefix rep: <http://www.openrdf.org/config/repository#>.
@prefix sr: <http://www.openrdf.org/config/repository/sail#>.
@prefix sail: <http://www.openrdf.org/config/sail#>.
@prefix owlim: <http://www.ontotext.com/trree/owlim#>.
[] a rep:Repository ;
rep:repositoryID "Riddle" ;
rdfs:label "Einstein Riddle Getting Started" ;
rep:repositoryImpl [
rep:repositoryType "openrdf:SailRepository" ;
sr:sailImpl [
sail:sailType "owlim:Sail" ;
owlim:base-URL "http://www.iis.nsk.su/persons/ponom/ontologies/einsteins_riddle_en.owl#" ;
# There must be exactly the same number of semicolon separated entries in
# the defaulNS and imports fields
owlim:defaultNS "http://www.iis.nsk.su/persons/ponom/ontologies/einsteins_riddle_en.owl#" ;
owlim:imports "./ontology/zebra.owl" ;
owlim:entity-index-size "5000000" ;
owlim:repository-type "file-repository" ;
owlim:ruleset "owl-max" ;
owlim:storage-folder "storage" ;
# OWLIM-SE parameters
owlim:cache-memory "180m" ;
# OWLIM-Lite parameters
owlim:noPersist "false" ;
# Other OWLIM-SE parameters
# owlim:enable-context-index "false" ;
owlim:check-for-inconsistencies "true" ;
# owlim:disable-sameAs "false" ;
owlim:enable-optimization "true" ;
owlim:enablePredicateList "true" ;
# owlim:entity-id-size "32" ; # 32/40
# owlim:fts-memory "20m" ;
# owlim:ftsIndexPolicy "never" ; # never/onStartup/onShutdown/onCommit
# owlim:ftsLiteralsOnly "false" ;
# owlim:in-memory-literal-properties "false" ;
# owlim:enable-literal-index "true" ;
# owlim:index-compression-ratio "-1" ; # -1/10-50
# owlim:owlim-license "" ;
# owlim:predicate-memory "80m" ;
# owlim:query-timeout "-1" ;
# owlim:tokenization-regex "[\p{L}\d_]+" ;
# owlim:tuple-index-memory "80m" ;
# owlim:useShutdownHooks "true" ;
# owlim:transaction-mode "safe" ;
# owlim:read-only "false" ;
# Other OWLIM-Lite parameters
# owlim:jobsize "1000}" ;
# owlim:new-triples-file ""
]
].
如果我使用owl2-rl或owl2-ql或w / e,则无关紧要。总是一样的结果。只有推断的三元组数量变为正数。
08:51:40 Executing query 'Who drinks What'
co kto
---------------------------------------------
einsteins_riddle_en:tea einsteins_riddle_en:Ukrainian
08:51:40 1 result(s) in 63ms.
08:51:40 Executing query 'Number of inferred triples'
count
---------------------------------------------
"770"^^<http://www.w3.org/2001/XMLSchema#integer>
推断三元组对我来说没用,样本:
p s o
---------------------------------------------
rdf:type rdf:type rdf:Property
rdf:type rdfs:subPropertyOf rdf:Property
rdf:type rdfs:subClassOf rdf:Property
rdf:type rdfs:domain rdf:Property
rdf:type rdfs:range rdf:Property
rdf:type owl:equivalentClass rdf:Property
rdf:type psys:transitiveOver rdf:Property
...
答案 0 :(得分:1)
是的,这是可能的,但这取决于您的OWLIM存储库的配置方式。
首次创建存储库时,OWLIM使用的推理规则集将设置为配置参数 - 有关详细信息,请参阅the configuration documentation。显然,如果您将其设置为使用空规则集,则根本不会进行推理。根据您选择的规则集(有几个级别的表达性),它将能够推断出更多或更少的三重奏(规则集越具表现力,信息越多)。
如果您的OWLIM存储库配置正确,查询将自动检索推断信息以及显式语句。
当然,这也取决于是否确实有任何可以推断的东西。您的查询在Protege和OWLIM中提供相同结果的事实可能仅仅意味着OWLIM 进行推理,但未找到任何与您的查询匹配的推断信息。