Question

表结构......

计划大师

book     receipt     coupon    created
 100       700       1200      12-03-2015
 100       700       1201      12-03-2015
 100       700       1202      12-03-2015
 100       701       1203      12-03-2015
 100       701       1204      12-03-2015
 100       701       1205      12-03-2015

图书问题表

  book_no    Alloted_city    issue_date   
  100         nagpur         15-03-2015
  100         nagpur         18-03-2015

Book_return表

 book     surveyor     used_receipt    city
 1000       raj          700           nagpur

以下是我的预期输出..

 book      printeddate    issuedate   balancereceipt  allcoupon        city
 100       12-03-2015     15-03-2015     701         1203,1204,1205    nagpur

以下是我的SQL查询。

这很好用..但需要4到5分钟才能执行50到80行... plz帮我优化以下查询......

SELECT DISTINCT BI.book_no AS book,BI.issue_date As Issuedate,BI.Alloted_city As city,SM.created AS PrintedDate,
     SM.receipt_no as AllReceipt,GROUP_CONCAT(DISTINCT SM.coupon ORDER BY coupon ASC) As Allcoupon FROM book_issue BI LEFT JOIN scheme_master SM ON SM.book_no2=BI.book_no WHERE SM.receipt_no NOT IN (select used_receipt from book_return) AND BI.Alloted_city = :cityname AND BI.book_no BETWEEN :book_no AND :book2 GROUP BY SM.receipt_no order by SM.receipt_no ASC

Answer 1

像这样使用，在非条件中添加where子句，

SELECT DISTINCT BI.book_no AS book,BI.issue_date As Issuedate,BI.Alloted_city As city,SM.created AS PrintedDate,
 SM.receipt_no as AllReceipt,GROUP_CONCAT(DISTINCT SM.coupon ORDER BY coupon ASC) As Allcoupon 
FROM book_issue BI 
LEFT JOIN scheme_master SM ON SM.book_no2=BI.book_no 
WHERE SM.receipt_no NOT IN (select used_receipt from book_return where used_receipt = SM.receipt_no) 
AND BI.Alloted_city = :cityname AND BI.book_no BETWEEN :book_no AND :book2 
GROUP BY SM.receipt_no order by SM.receipt_no ASC

sql查询优化执行时间，以过滤table1中不存在的table1中的数据

1 个答案: