在C中打印ASCII代码值及其等效字符

Question

如何为给定的ASCII码值打印char？..

我看到了这个question，我的问题很相似，只是相反

以下是我的计划，但它不起作用。

int main (){
int code;     // code that user enters
char ch;      //"codes" related ASCII charcter

printf("Enter a ASCII code value: \n");
scanf("%d", &code);
ch=code;

printf(" %c is cherechter that have %d ASCII code\n", &ch ,&code);

system("PAUSE");
return 0;}  

Answer 1

在您的代码中，您必须更改printf语句

printf(" %c is cherechter that have %d ASCII code\n", &ch ,&code);

到

printf(" %c is cherechter that have %d ASCII code\n", ch ,code);

因为要打印值，您不需要提供变量的地址。变量名就足够了。

Answer 2

将您的代码更改为：

int main (){
char code;   //change from int to char  
char ch;      

printf("Enter a ASCII code value: \n");
scanf("%c", &code);//ASCII is a character not integer
ch=code;

printf(" %c is cherechter that have %x and %d ASCII code\n", ch ,code,code);//don't print the address access the value

system("PAUSE");
return 0;}