Question

这是我的代码：

rows = subprocess.check_output("ls -1t | grep 'syslogdmz'", shell=True)

我得到的结果是两个文件名，但我不明白它为什么不把它们放在一个列表中。有办法吗？

谢谢

Answer 1

您可能想要使用os.popen：

from os import popen
rows = popen("ls -1t | grep 'syslogdmz'","r").readlines()

rows会将结果包含在列表中。

Answer 2

来自文档https://docs.python.org/2/library/subprocess.html#subprocess.check_output

“使用参数运行命令并将其输出作为字节字符串返回。”

不确定为什么要获得列表。

Answer 3

请参阅手册页。

>>> import subprocess
>>> help(subprocess.check_output)
Help on function check_output in module subprocess:

check_output(*popenargs, **kwargs)
    Run command with arguments and return its output as a byte string.

    If the exit code was non-zero it raises a CalledProcessError.  The
    CalledProcessError object will have the return code in the returncode
    attribute and output in the output attribute.

    The arguments are the same as for the Popen constructor.  Example:

    >>> check_output(["ls", "-l", "/dev/null"])
    'crw-rw-rw- 1 root root 1, 3 Oct 18  2007 /dev/null\n'

    The stdout argument is not allowed as it is used internally.
    To capture standard error in the result, use stderr=STDOUT.

    >>> check_output(["/bin/sh", "-c",
    ...               "ls -l non_existent_file ; exit 0"],
    ...              stderr=STDOUT)
    'ls: non_existent_file: No such file or directory\n'

>>>

尝试使用os.popen获取列表中的输出。或者使用split（）进入列表。

x = os.popen('ls -1t | grep syslogdmz').readlines()
print x

Python将stdout作为列表

3 个答案: