Question

我正在尝试将逗号分隔的电子邮件ID列表传递给@b.com，s @ b.com进入sql in子句是我的查询权请提供一些建议

 SELECT * FROM service.cs_list_of_email_ids where Email in (
        SELECT regexp_substr(:a@b.com,s@b.com,'[^,]+', 1, level) items
        FROM dual
        CONNECT BY regexp_substr(:a@b.com,s@b.com, '[^,]+', 1, level) is not null
    );

Answer 1

由于您没有提及是否使用Sql Server，因此可以创建此函数以拆分逗号分隔的字符串

CREATE FUNCTION Split
(
  @delimited nvarchar(max),
  @delimiter nvarchar(100)
) RETURNS @t TABLE
(
-- Id column can be commented out, not required for sql splitting string
  id int identity(1,1), -- I use this column for numbering splitted parts
  val nvarchar(max)
)
AS
BEGIN
  declare @xml xml
  set @xml = N'<root><r>' + replace(@delimited,@delimiter,'</r><r>') + '</r></root>'

  insert into @t(val)
  select
    r.value('.','varchar(max)') as item
  from @xml.nodes('//root/r') as records(r)

  RETURN
END
GO

然后将其称为

SELECT * FROM service.cs_list_of_email_ids where Email in 
       (SELECT val FROM dbo.split(@str,','))

如何将逗号分隔列表发送到in子句中？

1 个答案: