Question

我有两个数据帧被清理并合并为一个csv文件，数据帧是这样的

  **Source                         Master**

 chang chun petrochemical      CHANG CHUN GROUP
 chang chun plastics           CHURCH AND DWIGHT CO INC
 church  dwight                CITRIX SYSTEMS ASIA PACIFIC P L
 citrix systems  pacific       CNH INDUSTRIAL N.V

现在从这些开始，我必须考虑名字并检查主名称的每个名称并找到相关的匹配并将输出打印为另一个数据框。以上数据框很少，但我正在使用20k值。

我的输出必须如下所示

 **Source                         Master                         Result**

 chang chun petrochemical      CHANG CHUN GROUP                 CHANG CHUN GROUP
 chang chun plastics           CHURCH AND DWIGHT CO INC         CHANG CHUN GROUP
 church  dwight                CITRIX SYSTEMS ASIA PACIFIC P L  CHURCH AND DWIGHT CO INC
 citrix systems  pacific       CNH INDUSTRIAL N.V               CITRIX SYSTEMS ASIA PACIFIC P L

我尝试使用此链接Merging through fuzzy matching of variables in R可能的方法，但到目前为止没有运气......！

提前感谢!!

当我将上述代码用于大量数据时，结果就是这个 -

使用的代码：

Mast <- pmatch(Names$I_sender_O_Receiver_Customer, Master.Names$MOD, nomatch=NA)

输出

NA NA  2  3 NA NA NA  6 NA NA  9 NA NA NA 12 NA NA NA 13 14 15 16 NA 18 19 20 21 22 NA 24 NA 26 NA 28 NA NA NA 30 NA NA 33 NA 35 36 37 NA 39 40 NA NA 43 NA 45 46 NA 48 49 50 51 52 53 54 55 56 57 58 NA
 [68] 60 61 62 NA NA NA NA 64 NA 66 67 68 69 70 71 72 73 NA 75 76 77 78 NA 79 80 81 NA 83 84 85 86 87 88

CODE：

Mast <- sapply(Names$I_sender_O_Receiver_Customer, function(x) {
   agrep(x, Master.Names$MOD,value=TRUE) })

输出：

[[1]]
character(0)

[[2]]
character(0)

[[3]]
[1] " CHURCH AND DWIGHT CO INC"

[[4]]
[1] " CITRIX SYSTEMS ASIA PACIFIC P L"

[[5]]
character(0)

即使使用for循环，也不会产生任何结果。

码

for(i in seq_len(nrow(df$ICIS_Cust_Names)))
  {
    df$reslt[i] <- grep(x = str_split(df$ICIS_Cust_Names[i]," ")[[1]][1], df$Master_Names[i],value=TRUE)
  }
  print(df$reslt)

代码2： 仅用于100行的循环

for (i in 100){
  gr1$x[i] = agrep(gr1$ICIS_Cust_Names[i], gr2$Master_Names, value = TRUE, max = list(del = 0.2, ins = 0.3, sub = 0.4))
  gr2$Y[i] = agrep(gr1$ICIS_Cust_Names[i], gr2$Master_Names, value = FALSE, max = list(del = 0.2, ins = 0.3, sub = 0.4))
}

结果：

NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA

错误

Error in `$<-.data.frame`(`*tmp*`, "x", value = c(NA, NA, " church  dwight  " : 
  replacement has 3 rows, data has 100

当观察到上面的结果被考虑时，因为它直接检查每个数据帧的行值，但我希望它考虑Source的第一个元素并检查master的所有元素和想出一个匹配，同样休息。如果有人能纠正我的代码，我将不胜感激！提前致谢..！

Answer 1

如果你只想对名字中的第一个单词检查Master.Names，这可以解决问题：

Names$Mast <- NA
for(i in seq_len(nrow(Names))) 
    Names$Mast[i] <- grep(toupper(x = strsplit(Names[i,1]," ")[[1]][1]), Master.Names$V1,value=TRUE)

修改

使用sapply代替循环可以获得一些速度：

Names$Mast <- sapply(Names$V1, function(x) {
    grep(toupper(x = strsplit(x," ")[[1]][1]), Master.Names$V1,value=TRUE)
})

<强>结果

> Names
                        V1                            Mast
1 chang chun petrochemical                CHANG CHUN GROUP
2      chang chun plastics                CHANG CHUN GROUP
3            church dwight        CHURCH AND DWIGHT CO INC
4   citrix systems pacific CITRIX SYSTEMS ASIA PACIFIC P L

数据

Master.Names <- read.csv(text="CHANG CHUN GROUP CHURCH AND DWIGHT CO INC CITRIX SYSTEMS ASIA PACIFIC P L CNH INDUSTRIAL N.V", header=FALSE) Names <- read.csv(text="chang chun petrochemical chang chun plastics church dwight citrix systems pacific", header=FALSE)

找到两个数据帧的匹配并将答案重写为数据帧

1 个答案: