Question

执行以下操作的最佳方法是什么？示例文档（hello.txt）包含以下内容：

>>> repr(hello.txt) #show object representations 

Hello there! This is a sample text. \n Ten plus ten is twenty. \n Twenty times two is forty \n 

>>> print(hello.txt) 

Hello There. This is a sample text 
Ten plus ten is twenty 
Twenty times two is forty

待办事项： 打开一个文件，将每一行拆分成一个列表，然后对每行中的每个单词检查该单词是否在列表中，如果没有将其附加到列表中

open_file = open('hello.txt')
lst = list() #create empty list 

for line in open_file:     
    line = line.rstrip()   #strip white space at the end of each line 
    words = line.split()   #split string into a list of words 

    for word in words:
        if word not in words:
            #Missing code here; tried 'if word not in words', but then it produces a empty list 
            lst.append(word) 

lst.sort()
print(lst)

以上代码的输出：

['Hello', 'Ten', 'There', 'This', 'Twenty', 'a', 'forty', 'is', 'is', 'is', 'plus', 'sample', 'ten', 'text', 'times', 'twenty', 'two']

当'is'字符串只出现一次时，它会出现3次。我一直在想弄清楚如何编写代码来检查每一行上的每个单词，看看这个单词是否在列表中，如果没有附加到列表中......

期望的输出：

['Hello', 'Ten', 'There', 'This', 'Twenty', 'a', 'forty', 'is', 'plus', 'sample', 'ten', 'text', 'times', 'twenty', 'two']

Answer 1

套装是唯一会员资格的理想选择。

hello.txt的内容：

Hello there! This is a sample text. 
 Ten plus ten is twenty. 
 Twenty times two is forty

代码：

result = set()

with open('hello.txt', 'r') as myfile:
    for line in myfile:
        temp = [result.add(item) for item in line.strip().split()]

for item in result:
    print(item)

结果：

text.
Twenty
This
ten
a
sample
times
twenty.
Hello
is
there!
two
forty
plus
Ten

你也可以修改你的代码来说if word not in lst而不是if word not in words，然后就可以了。

如果你想对一个集合进行排序......好吧，集合是无序的，但你可以用sorted(result)对输出进行排序。

Answer 2

您的错误在于以下两行：

for word in words:
     if word not in words:

也许你的意思是：

for word in words:
     if word not in lst:

无论价值多少，以下是我编写整个程序的方法：

import string
result = sorted(set(
    word.strip(string.punctuation)
    for line in open('hello.txt')
    for word in line.split()))
print result

Answer 3

解决方案：

open_file = open('hello.txt') #open file 

lst = list() #create empty list 


for line in open_file:  #1st for loop strip white space and split string into list of words 
    line = line.rstrip()
    words = line.split()
    for word in words:  #nested for loop, check if the word is in list and if not append it to the list
        if word not in lst:
            lst.append(word)

lst.sort() #sort the list of words: alphabetically 
print(lst) #print the list of words

打开一个文件，将每一行拆分成一个列表，然后对每行中的每个单词检查该单词是否在列表中，如果没有将其附加到列表中

3 个答案: