Question

我有一张桌子（SoilSheet）：

ID | FieldID | SAMP_NUM | LINE_NUM | Year

LINE_NUM列是介于1和25之间的值。我需要查找具有LINE_NUM行的DISTINCT SAMP_NUM和FieldID ROWS并将它们返回到一行。

在SQL Server中，我可以这样做（缩短为仅返回前5个LINE_NUM列，它几乎立即起作用：

SELECT DISTINCT S1.L1, S2.L2, S3.L3, S4.L4, S5.L5, 
  S.FieldID, S.SAMP_NUM FROM SoilSheet S
LEFT OUTER JOIN
  (SELECT SAMP_NUM, FieldID, LINE_NUM AS L1 
  FROM SoilSheet WHERE YEAR = 2013 AND LINE_NUM = 1) S1 
  ON S1.SAMP_NUM = S.SAMP_NUM AND S1.FieldID = S.FieldID
LEFT OUTER JOIN
  (SELECT SAMP_NUM, FieldID, LINE_NUM AS L2 
  FROM SoilSheet WHERE YEAR = 2013 AND LINE_NUM = 2) S2 
  ON S2.SAMP_NUM = S.SAMP_NUM AND S2.FieldID = S.FieldID
LEFT OUTER JOIN
  (SELECT SAMP_NUM, FieldID, LINE_NUM AS L3 
  FROM SoilSheet WHERE YEAR = 2013 AND LINE_NUM = 3) S3 
  ON S3.SAMP_NUM = S.SAMP_NUM AND S3.FieldID = S.FieldID
LEFT OUTER JOIN
  (SELECT SAMP_NUM, FieldID, LINE_NUM AS L4 
  FROM SoilSheet WHERE YEAR = 2013 AND LINE_NUM = 4) S4 
  ON S4.SAMP_NUM = S.SAMP_NUM AND S4.FieldID = S.FieldID
LEFT OUTER JOIN
  (SELECT SAMP_NUM, FieldID, LINE_NUM AS L5 
FROM SoilSheet WHERE YEAR = 2013 AND LINE_NUM = 5) S5 
  ON S5.SAMP_NUM = S.SAMP_NUM AND S5.FieldID = S.FieldID
LEFT OUTER JOIN
  (SELECT SAMP_NUM, FieldID, LINE_NUM AS L10 
FROM SoilSheet WHERE YEAR = 2013 AND LINE_NUM = 10) S10 
  ON S10.SAMP_NUM = S.SAMP_NUM AND S10.FieldID = S.FieldID
WHERE Year = 2013 AND 
  (SELECT ID FROM Fields WHERE ID=S.FieldID) IS NOT NULL 
  ORDER BY S.SAMP_NUM, S.FieldID

我得到了这个

L1   | L2   | L3   | L4   | L5   | FieldID | SAMP_NUM
1    | NULL | NULL | NULL | NULL | 289508  | 4416
1    | NULL | NULL | NULL | NULL | 291501  | 4417
NULL | NULL |   3  | NULL | NULL | 291339  | 4418
NULL |    2 | NULL | NULL | NULL | 291390  | 4418
1    | NULL | NULL | NULL | NULL | 291535  | 4418
1    |    2 |    3 | NULL | NULL | 287808  | 4470
NULL | NULL | NULL |    4 |    5 | 287811  | 4470

但是，转换为MS Access时，这需要永远。我也试过下面这个在SQL Server中慢得多的东西：

SELECT DISTINCT  
(SELECT LINE_NUM FROM SoilSheet WHERE LINE_NUM = 1 AND Year = 2013 
AND FieldID = S.FieldID AND SAMP_NUM = S.SAMP_NUM) AS L1,
(SELECT LINE_NUM FROM SoilSheet WHERE LINE_NUM = 2 AND Year = 2013 
AND FieldID = S.FieldID AND SAMP_NUM = S.SAMP_NUM) AS L2,
(SELECT LINE_NUM FROM SoilSheet WHERE LINE_NUM = 3 AND Year = 2013 
AND FieldID = S.FieldID AND SAMP_NUM = S.SAMP_NUM) AS L3,
(SELECT LINE_NUM FROM SoilSheet WHERE LINE_NUM = 4 AND Year = 2013 
AND FieldID = S.FieldID AND SAMP_NUM = S.SAMP_NUM) AS L4,
(SELECT LINE_NUM FROM SoilSheet WHERE LINE_NUM = 5 AND Year = 2013 
AND FieldID = S.FieldID AND SAMP_NUM = S.SAMP_NUM) AS L5,
FieldID, SAMP_NUM FROM SoilSheet S
WHERE Year = 2013 AND (SELECT ID FROM Fields WHERE ID = S.FieldID) 
IS NOT NULL ORDER BY S.SAMP_NUM, S.FieldID

但也永远在Access中。有没有办法在Access中执行此操作？

Answer 1

我找到了办法：

TRANSFORM LINE_NUM AS L
SELECT SAMP_NUM, FieldID FROM SoilSheet WHERE Year = 2013
GROUP BY SAMP_NUM, FieldID  
PIVOT LINE_NUM

在Access中查找行中的列

1 个答案: