Java Matrix擦除

Question

我正在尝试删除.txt文件中的每个X.选择坐标时，如果是X，则应替换为0，然后还应替换每个接触它的X（对角线除外），直到不再有坐标为止。 X可以触及。我目前的代码没有得到这些结果。

当我在java.lang.ArrayIndexOutOfBoundsException: 9的{​​{1}}和0 getCoord(grid.length, "row")输入2时，我收到此错误getCoord(grid[0].length, "column")。

谢谢你的帮助。

的 image1.txt

main()

的 eraseImage.java

00X000000
0XXXXXXX0
0X00000XX
0X0X000XX
0X00000X0
0XXXXXXX0
XXXX00XX0
000XX0000

Answer 1

您需要在rubOut函数中添加边界检查：

public static void rubOut(String[][] g, int tRow, int tCol)
{
     if((tRow < 0) || (tRow >= g.length))
         return;
     if((tCol < 0) || (tCol >= g[tRow].length))
         return;

     ...
}

即使你的row = 0和column = 2的初始索引在边界内，当你调用rubOut(g, tRow - 1, tCol);时你也会超出范围，因为tRow将是-1。

Answer 2

使用此for循环替换X over 0

public static void main(String [] args){
    String[][] str ={{"0","0","X","0","0","0","0","0","0"},
            {"0","X","X","X","X","X","X","X","0"},{"0","X","0","0","0","0","0","X","X"},
            {"0","X","0","X","0","0","0","X","X"},{"0","X","0","0","0","0","0","X","0"},};

    for (int i=0; i<str.length; i++) {
        for(int j=0; j<str[i].length; j++){
            System.out.print(str[i][j]);
        }
        System.out.println();
    }

    System.out.println();

    for (int i=0; i<str.length; i++) {
        for(int j=0; j<str[0].length; j++){
            if(i==j){
                str[i][j]="0";
            }
            System.out.print(str[i][j]);
        }
        System.out.println();
    }
}

这将取代X超过0