Question

我在几个小时内解决了这个问题但没有结果。我需要的是当用户登录时，每个人都会看到他在线。我已经完成了但问题是当有人刷新页面时。然后用户断开连接并返回连接，结果是我有一个双重性而不只是更新。这是我在服务器端的内容：

clients = [];

io.on('connection', function (socket) {

    if (socket.request.user.username in clients) {

        io.emit('chatMessage', {
            type: 'status',
            text: 'connected',
            created: Date.now(),
            username: socket.request.user.username,
            user_id: socket.request.user._id,
            socket_id: socket.id
        });


    } else {
        console.info('New client connected (id=' + socket.id + ').');
        // after connect set socket ID to username
        clients[socket.request.user.username] = socket.id;


    }

    socket.on('disconnect', function () {

        delete clients[socket.request.user.username];

    });
});

在客户端：

angular.module('messages')
    .controller('MessagesController', ['$scope', 'Socket', 'Authentication',
        function ($scope, Socket, Authentication) {

            $scope.authentication = Authentication;

            $scope.messages = [];
            Socket.on('chatMessage', function (message) {
                $scope.messages.push(message);
            });
        }
    ]);

观点：

<section data-ng-controller="MessagesController">
                    <div data-ng-repeat="message in messages" data-ng-switch="message.type">
                        <strong data-ng-switch-when='status'>
                            <span data-ng-bind="message.created | date:'mediumTime'"></span>
                            <span data-ng-bind="message.username"></span>
                            <span>is</span>
                            <span data-ng-bind="message.text"></span>
                            <span data-ng-bind="message.user_id"></span>
                            <span>Socket.io ID is </span>
                            <span data-ng-bind="message.socket_id"></span>
                        </strong>
                    </div>
                </section>

结果就是这样：

12:08:38 AM jerry.klimcik is connected 5515ce05207842d412c07e03 Socket.io ID je URYiTSu4Zy0In2wNAAAL
12:27:30 AM admin is connected 55156119ec0b97ec217d8197 Socket.io ID is RcP_tyHarb5sN0XoAAAN
12:27:32 AM admin is connected 55156119ec0b97ec217d8197 Socket.io ID is 7dumGFZzgJunF49cAAAO

用户admin刷新页面，现在我看到他被记录了两次。我只想保留他最后的联系。我非常绝望。

Answer 1

如果我理解你的问题，那么事实是你在创建用户时而不是在创建用户之后发送连接消息。

因此，这个块：

if (socket.request.user.username in clients) {

    io.emit('chatMessage', {
        type: 'status',
        text: 'connected',
        created: Date.now(),
        username: socket.request.user.username,
        user_id: socket.request.user._id,
        socket_id: socket.id
    });


} else {
    console.info('New client connected (id=' + socket.id + ').');
    // after connect set socket ID to username
    clients[socket.request.user.username] = socket.id;


}

应该被这样的东西取代：

if (!clients.hasOwnProperty(socket.request.user.username)) {
    console.info('New client connected (id=' + socket.id + ').');
    // after connect set socket ID to username
    clients[socket.request.user.username] = socket.id;

    io.emit('chatMessage', {
        type: 'status',
        text: 'connected',
        created: Date.now(),
        username: socket.request.user.username,
        user_id: socket.request.user._id,
        socket_id: socket.id
    });

}

然后，客户端的会话依赖于他的用户名。

Socket.io - 在用户刷新页面时覆盖文本

1 个答案: