我的第一个Java程序出了问题。我试图重现你玩过比赛的游戏,但该程序永远都不会停止...
当我输入6,3,2,1或7,3,2,1等数字时,循环应停在那里,但它只是继续到下一个转弯,好像什么也没发生,即使变量具有正确的值,应符合最终条件。
我很确定问题出在主循环的while部分(最后),但我无法看到它!它可能是显而易见的,但是很好......
以下是完整的源代码(游戏规则在其下方):
import java.util.Scanner;
public class JeuDeNim {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
//Starting the game
int totalMatches;
do {
System.out.println("How many matches do you want to play with? "
+ "(from 6 to 60)");
totalMatches = sc.nextInt();
}
while(totalMatches < 6 || totalMatches > 60);
int matchesPlayer1 = 0;//to keep track of
int matchesPlayer2 = 0;//the previous round
int i = 1;//to know whose turn it is
do{
//player 1
if(!(i % 2 == 0)) {//if odd number, player 1
//round 1
if(i == 1) {
do {
System.out.println("Player 1: How many matches do you "
+ "want to pick? (1, 2 or 3)");
matchesPlayer1 = sc.nextInt();
}
while(matchesPlayer1 < 1 || matchesPlayer1 > 3);
totalMatches = totalMatches - matchesPlayer1;
i++;
}
//odd round x
else {
do {
System.out.println("Player 1: How many matches do you "
+ "want to pick this turn?");
matchesPlayer1 = sc.nextInt();
if(totalMatches - matchesPlayer1 < 0) {
System.out.println("Pick a smaller number");
//totalMatches cannot be negative
} else if(matchesPlayer1 == matchesPlayer2) {
System.out.println("You cannot pick the same number "
+ "of matches as Player 2");
}
}
while(matchesPlayer1 < 1 || matchesPlayer1 > 3
|| (totalMatches - matchesPlayer1 < 0)
|| (matchesPlayer1 == matchesPlayer2));
totalMatches = totalMatches - matchesPlayer1;
if(totalMatches == 0
|| (totalMatches == 1 && matchesPlayer1 == 1)) {
System.out.println("Player 1 Wins!");
}
i++;
}
}
//player 2
else {
//round 2
if(i == 2) {
do {
System.out.println("Player 2: How many matches do you "
+ "want to pick? (1, 2 or 3)");
matchesPlayer2 = sc.nextInt();
if(matchesPlayer2 == matchesPlayer1) {
System.out.println("You cannot pick the same "
+ "number of matches as Player 2");
}
}
while(matchesPlayer2 < 1 || matchesPlayer2 > 3
|| matchesPlayer2 == matchesPlayer1);
totalMatches = totalMatches - matchesPlayer2;
i++;
}
//even round x
else {
do {
System.out.println("Player 2: How many matches do you "
+ "want to pick this turn?");
matchesPlayer2 = sc.nextInt();
if (totalMatches - matchesPlayer2 < 0) {
System.out.println("Pick a smaller number");
//totalMatches cannot be negative
} else if(matchesPlayer2 == matchesPlayer1) {
System.out.println("You cannot pick the same number "
+ "of matches as Player 1");
}
}
while(matchesPlayer2 < 1 || matchesPlayer2 > 3
|| (totalMatches - matchesPlayer2 < 0)
|| (matchesPlayer2 == matchesPlayer1));
totalMatches = totalMatches - matchesPlayer2;
if(totalMatches == 0
|| (totalMatches == 1 && matchesPlayer2 == 1)) {
System.out.println("Player 2 Wins!");
}
i++;
}
}
System.out.println("totalMatches: " + totalMatches + " "
+ "matchesPlayer1: " + matchesPlayer1 + " " + "matchesPlayer2: "
+ matchesPlayer2);//to check that everything is working. It is not...
}
while(totalMatches > 0
|| !(!(i % 2 == 0) && totalMatches == 1 && matchesPlayer1 == 1)
|| !((i % 2 == 0) && totalMatches == 1 && matchesPlayer2 == 1));
}
}
以下是游戏规则:它是一个双人游戏,玩家轮流挑选比赛(1,2或3)并且不能选择与其他玩家相同数量的比赛:如果玩家一个选择2场比赛,选手2将选择1或3场比赛。无法再选择比赛的玩家将失去游戏,这意味着有两种结束场景:当没有更多比赛时,或者有1但其他玩家在上一轮比赛中选择了1。
答案 0 :(得分:1)
当没有剩余比赛时,比赛结束。所以while(totalMatches > 0);
就足够了。
删除不必要的行:
|| !(!(i % 2 == 0) && totalMatches == 1 && matchesPlayer1 == 1)
|| !((i % 2 == 0) && totalMatches == 1 && matchesPlayer2 == 1));
答案 1 :(得分:1)
查看最终while
循环中的条件
totalMatches > 0 ||
!(!(i % 2 == 0) && totalMatches == 1 && matchesPlayer1 == 1) ||
!((i % 2 == 0) && totalMatches == 1 && matchesPlayer2 == 1));
这意味着只要剩下任何比赛,循环就会重复,或者玩家1的回合剩下1场比赛并且选择1场比赛,或者它不是玩家2轮到剩下1场比赛并且选择1场比赛。
这种情况永远不会发生,因为(除其他原因外),它需要i%2==0
和i%2 != 0
。将||
切换为&&
,它应该可以解决问题。正如评论中指出的那样,你还需要反转玩家转弯检查,因为转弯计数器已经增加了这一点。
您希望在&&
使用此||
代替{{1}}的原因,就像您代码中的其他位置一样,您需要检查其他概念。每隔一段时间,您都要检查循环应该重复的原因。这一次,您检查循环应该结束的原因,并否定它们。如果有疑问,实际上插入比较值,看看它是否符合你的想法。