我想在搜索关键字时获取数据的json格式,所以我使用LIKE子句并像这样查询
"select * from employees where fname like ? or mname like ? or lname like ? or username like ? or id like ?", str, str, str, str, str
但我想用rails编写代码。我的控制器中有这个代码
def showemployees
str = params[:str]
render json: @employee = Employee.where(Employee.employees[:fname].matches("%#{str}%")) or
(Employee.employees[:mname].matches("%#{str}%")) or
(Employee.employees[:lname].matches("%#{str}%")) or
(Employee.employees[:id].matches("%#{str}%"))
end
和我的config / routes.rb中的这段代码
get 'employees/showemployees'
root :to => 'employees#new'
resources :employees
post 'employees/update_info'
当我输入http://localhost:3000/employees/showemployees?str=samplename时,应该出现记录的json格式但是我收到了此错误消息
undefined method `employees' for #<Class:0x8e38900>
app/controllers/employees_controller.rb:6:in `showemployees'
第6行有此代码
render json: @employee = Employee.where(Employee.employees[:fname].matches("%#{str}%")) or
答案 0 :(得分:6)
您可以将查询链接到哪里,但查询结果
的每个AND
Employee.where('fname LIKE ?', "%#{str}%").where('lname LIKE ?', "%#{str}%").where('mname LIKE ?', "%#{str}%").where('username LIKE ?', "%#{str}%").where('id LIKE ?', "%#{str}%")
或使用OR
子句
Employee.where('fname LIKE ? OR lname LIKE ? OR mname', "%#{str}%", "%#{str}%", "%#{str}%")