查找JSON文件是否包含字符串并返回机场名称

Question

我有一个相当大的JSON文件，其中包含完整的机场列表及其各自的信息（总共46000行）。

我希望能够检查JSON文件是否包含ICAO，然后在变量中返回机场名称。

理想情况下这样（仅作为示例）

if ($jsonFile contains $icao) {

    $airportName = airport_name of $icao;

} else {
    echo 'Sorry, that ICAO could not be found';
}

JSON提取：

[
{
    "complete_location": "Anaa, Tuamotus, French Polynesia",
    "iata_code": "AAA",
    "city": "Anaa",
    "icao_code": "NTGA",
    "country": " French Polynesia",
    "airport_name": "Anaa Airport"
},
{
    "complete_location": "Arrabury, Queensland, Australia",
    "iata_code": "AAB",
    "city": "Arrabury",
    "icao_code": "YARY",
    "country": " Australia",
    "airport_name": "Arrabury Airport"
},
{
    "complete_location": "El Arish, Egypt",
    "iata_code": "AAC",
    "city": "El Arish",
    "icao_code": "HEAR",
    "country": " Egypt",
    "airport_name": "El Arish International Airport"
},

实施例

如果我进入国际民航组织YARY我会收到机场名称Arrabury Airport

个人尝试：

到目前为止，我已设法在网页中打印所有json数据：

使用以下代码：

<?php
    // The JSON file location
    $JSONdatas = file_get_contents('icao/datas/city_airport_codes.json');
    $ARRAYdatas = json_decode($JSONdatas);

?>

<div>
    <div>
        <table>
            <thead>
                <tr>
                    <th width="200">IATA Codes</th>
                    <th width="200">ICAO Codes</th>
                    <th width="200">Airport Names</th>
                    <th>Locations</th>
                    <th width="150">Cities</th>
                    <th width="150">Countries</th>
                </tr>
            </thead>
            <tbody>
                <?php
                    $rows = '';
                    foreach($ARRAYdatas as $key => $airport)
                    {
                        $rows .= '
                        <tr>
                            <td>'.$airport->iata_code.'</td>
                            <td>'.$airport->icao_code.'</td>
                            <td>'.$airport->airport_name.'</td>
                            <td>'.$airport->complete_location.'</td>
                            <td>'.$airport->city.'</td>
                            <td>'.$airport->country.'</td>
                        </tr>
                        ';
                    }
                    echo $rows;
                ?>
            </tbody>
        </table>
    </div>
</div>

但我不确定从哪里开始！

感谢。

Answer 1

这是我的解决方案：

$condition = 'YARY';
$airports = array_filter($ARRAYdatas, function($item) use(&$condition) {
    return isset($item->icao_code) && $item->icao_code == $condition; 
});

$airport = array_pop($airports);
$airportName = $airport ? $airport->airport_name : '';

可能有一个更优雅或更快的解决方案，但我认为通过这种方式实现目标非常容易。

Answer 2

如果您正在寻找一些性能提升，那么以本机PHP格式缓存json_decode()输出并包含该文件可能是一个很好的调用。假设您在每个页面加载时包含.json文件。 （使用var_export()将数据转储为PHP可读格式。）

Answer 3

如果您熟悉回调，也可以使用：

function isICAO($Icao = NULL, $_json = array())
{
    array_walk($_json, function($item, $key) use($Icao){
        if($item->icao_code == $Icao) { echo $item->airport_name; }
    });
}
// Print Airport name if icao_code is found. Else nothing.
echo isICAO("NTGA", $_json);

回调之前的老路

<?php
function isICAO($Icao = NULL, $_json = array())
{
    foreach ($_json as $key => $item)
    {
        if($item->icao_code == $Icao) 
        {
            return $item->airport_name;
        }
    }
    return false;
}

if($Airport = isICAO("NTGA", $_json))
{
    echo $Airport;
}
else
{
    echo "Sorry, that ICAO could not be found";
}
?>

Javascript代码：     

var json = [
    {
        "complete_location": "Anaa, Tuamotus, French Polynesia",
        "iata_code": "AAA",
        "city": "Anaa",
        "icao_code": "NTGA",
        "country": " French Polynesia",
        "airport_name": "Anaa Airport"
    },
    {
        "complete_location": "Arrabury, Queensland, Australia",
        "iata_code": "AAB",
        "city": "Arrabury",
        "icao_code": "YARY",
        "country": " Australia",
        "airport_name": "Arrabury Airport"
    },
    {
        "complete_location": "El Arish, Egypt",
        "iata_code": "AAC",
        "city": "El Arish",
        "icao_code": "HEAR",
        "country": " Egypt",
        "airport_name": "El Arish International Airport"
    }
];

function isICAO(Icao)
{
    var result = [];
    json.map(function(value, index) {
        if(value.icao_code == Icao) { result.push(value); }
    });
    return result;
}

console.log(isICAO('HEAR'));

</script>