Question

我在转换以下SQL查询以使用laravels查询构建器时遇到了很多麻烦。

SELECT * FROM gifts 
JOIN giftcategory ON gifts.id = giftcategory.giftid
JOIN giftoccasions ON gifts.id = giftoccasions.giftid
JOIN giftrelationship ON gifts.id = giftrelationship.giftid

WHERE (gifts.gender = 'any' OR gifts.gender = 'male')
AND giftoccasions.occasionid = '2'
AND (giftcategory.categoryid = '0' OR giftcategory.categoryid = '1')
AND giftrelationship.relationshipid = '1'

此查询工作正常，但在使用Laravels查询构建器时，我无法获得相同的结果。到目前为止，我有以下代码。它根本无法正常工作。我认为问题可能在于orWhere部分，因为它似乎返回了与其他where子句不匹配的结果。

$giftQuery = DB::Table('gifts')
->Join('giftcategory', 'gifts.id', '=', 'giftcategory.giftid')
->Join('giftoccasions', 'gifts.id', '=', 'giftoccasions.giftid')
->where('gifts.gender', '=', "male")
->orwhere('gifts.gender', '=', "any")
->where('giftoccasions.occasionid', '=', "2")
->where('giftoccasions.relationshipid', '=', "1")
->Where('giftcategory.categoryid', '=', "0")
->orWhere('giftcategory.categoryid', '=', "1");

Answer 1

您希望advanced where使用参数分组：

$giftQuery = DB::table('gifts')
    ->join('giftcategory', 'gifts.id', '=', 'giftcategory.giftid')
    ->join('giftoccasions', 'gifts.id', '=', 'giftoccasions.giftid')
    ->where(function($query) {
        $query->where('gifts.gender', '=', "male")
            ->orWhere('gifts.gender', '=', "any");
    })
    ->where('giftoccasions.occasionid', '=', "2")
    ->where('giftoccasions.relationshipid', '=', "1")
    ->where('giftcategory.categoryid', '=', "0")
    ->orWhere('giftcategory.categoryid', '=', "1");

在laravel查询构建器中使用多个where子句

1 个答案: