我在Pivot上看过各种帖子或将行转换为列,但我仍然没有运气,所以我决定发布这个问题。
我的表 cols 是
Id col_name
1 Serial
2 Data1
3 Data2
我的表行是
Id col_id value
1 1 1
2 1 2
3 1 3
4 2 25
5 2 26
6 2 27
7 3 28
8 3 29
9 3 30
我希望结果如下所示我认为使用unpivot或pivot可能会有效。出来的应该是 -
Serial Data1 Data2
1 25 28
2 26 29
3 27 30
任何帮助都会有所帮助。
答案 0 :(得分:1)
我将指出您的数据模型需要一些改进,因此我加入串行的方法是即兴的,并且在实际项目中不可信任,您的表之间没有逻辑连接。以下是如何转动数据:
;WITH [rows] AS
(
SELECT id, value, col_id
FROM
(values
(1,1,1),(2,1,2),
(3,1,3),(4,2,25),
(5,2,26),(6,2,27),
(7,3,28),(8,3,29),
(9,3,30)) x(Id, col_id, value)
), cols as
(
SELECT cols.id, col_name
FROM
(values
( 2, 'Data1'),( 3, 'Data2'))
cols(Id, col_name)
), result as
(
SELECT row_number() OVER (partition by col_id order by [rows].id) rn, col_name, value
FROM
cols
JOIN
[rows]
ON [rows].col_id = cols.id
WHERE cols.id > 1
)
SELECT rn Serial, Data1, Data2
FROM
result
PIVOT
(min([value])
FOR col_name
in([Data1],[Data2])
)AS p
结果:
Serial Data1 Data2
1 25 28
2 26 29
3 27 30
答案 1 :(得分:0)
我不认为pivot
在这里很有用。试试这个
WITH cte1
AS (SELECT Row_number()OVER(ORDER BY Id) RN,
value AS Data1
FROM yourtable
WHERE col_id = 1),
cte2
AS (SELECT Row_number()OVER(ORDER BY Id) RN,
value AS Data2
FROM yourtable
WHERE col_id = 2),
cte3
AS (SELECT Row_number()OVER(ORDER BY Id) RN,
value AS Data3
FROM yourtable
WHERE col_id = 3)
SELECT Row_number()OVER(ORDER BY a.rn) AS serial,
Data1,
Data2,
Data3
FROM cte1 A
FULL OUTER JOIN cte2 B
ON a.RN = b.RN
FULL OUTER JOIN cte3 C
ON b.RN = C.RN