Question

我有一个配置文件（nginx default.conf），我有这种字符串：

server {
        location / {
                proxy_set_header Host sudomain1.somewhere.com;
                proxy_pass         http://127.0.0.1:8999/;
                }
}
server {
        location / {
                proxy_set_header Host sudomain2.somewhere.com;
                proxy_pass         http://127.0.0.1:8755/;
                }
}
server {
        location / {
                proxy_set_header Host sudomain3.somewhere.com;
                proxy_pass         http://127.0.0.1:8525/;
                }
}

如何减去有关subdomain2的配置？

server {
        location / {
                proxy_set_header Host sudomain2.somewhere.com;
                proxy_pass         http://127.0.0.1:8755/;
                }
}

如果有可能，使用grep会很好！谢谢你的宝贵帮助！

Answer 1

您可以使用此gnu awk命令使用自定义记录分隔符（subdomain2）获取与RS匹配的块：

awk -v RS='}[[:space:]]*}[[:space:]]*' '/sudomain2/{printf $0 RT}' default.conf
server {
        location / {
                proxy_set_header Host sudomain2.somewhere.com;
                proxy_pass         http://127.0.0.1:8755/;
                }
}

编辑：打印除subdomain2以外的其他块：

awk -v RS='}[[:space:]]*}[[:space:]]*' '!/sudomain2/{printf $0 RT}' file
server {
        location / {
                proxy_set_header Host sudomain1.somewhere.com;
                proxy_pass         http://127.0.0.1:8999/;
                }
}
server {
        location / {
                proxy_set_header Host sudomain3.somewhere.com;
                proxy_pass         http://127.0.0.1:8525/;
                }
}

如何使用正则表达式删除文件中的字符串和相邻文本？

1 个答案: