QObject :: connect:没有这样的信号(classname)(signalname)(atribure)

时间:2015-03-28 16:25:22

标签: c++ qt signals signals-slots

我有问题。编译时一切都很棒,但插槽不起作用。应用程序启动后,它会输出QObject::connect: No such signal CMatrix::ReadyToDraw(ww)。我测试了它,插槽DrawFunction()不起作用。由于分段错误,我无法调试。

header.h

class CMatrix:public QObject
{
    Q_OBJECT
public:
    int **m_pMatrix;
    const short int m_size=4;
public:
    CMatrix();
    bool checkFields();
    void setField();
signals:
    void ReadyToDraw(CMatrix *ww);
public slots:
    void MoveDown();
    void MoveTop();
    void MoveLeft();
    void MoveRight();
};
class MainWindow : public QWidget
{
    Q_OBJECT
public:
MainWindow(QWidget *parent = 0);
    ~MainWindow();
private slots:
    void DrawFunction(CMatrix *A);
public:
    QPushButton* butTop;
    QList<QLabel*> lblList;
};

的main.cpp

#include "header.h"
#include <QApplication>

int main(int argc, char *argv[])
{
    QApplication a(argc, argv);
    MainWindow w;
    CMatrix *ww=new CMatrix;
    QObject::connect(w.butTop,SIGNAL(clicked()),ww,SLOT(MoveTop()));
    QObject::connect(ww,SIGNAL(ReadyToDraw(ww)),&w,SLOT(DrawFunction(ww)));
    w.show();


    return a.exec();
}

1 个答案:

答案 0 :(得分:1)

您的信号签名是

ReadyToDraw(CMatrix *)

ReadyToDraw(ww)

因为connect()需要类型,而不是变量的名称。

将连接线更改为:

QObject::connect(ww,SIGNAL(ReadyToDraw(CMatrix *)),&w,SLOT(DrawFunction(CMatrix *)));