这是一个包含Stack类和其他函数的程序。
ReadTheFile()
- 读取存储在num_file.txt
中的数字,并返回带有这些数字的向量。 IntervalCheck()
- 从输入向量中添加特定范围的数字,并返回仅包含这些数字的向量。 VecToMyStack()
- 将数字从向量添加到堆栈。
#include <iostream>
#include <string>
#include <vector>
#include <fstream>
#define STACK_EMPTY -1
#define OUT_OF_STACK -2
using namespace std;
template <class T>
class Stack {
private:
struct Node{
T element;
Node *prevElement;
};
size_t NumberOfElements;
Node *tempAdr;
Node *topElement;
Node *newElement;
Node *erasedElement;
public:
Stack(){
topElement = new Node;
topElement->prevElement = nullptr;
NumberOfElements = 0;
}
~Stack(){
cout << endl << "I'm a destructor";
while(NumberOfElements !=0 ){
tempAdr = topElement->prevElement;
delete topElement;
topElement = tempAdr;
NumberOfElements--;
}
delete topElement;
}
void push(T input_element){
tempAdr = topElement;
topElement = new Node;
topElement->element = input_element;
topElement->prevElement = tempAdr;
NumberOfElements++;
}
void pop(){
if (NumberOfElements == 0) throw STACK_EMPTY;
else {
tempAdr = topElement->prevElement;
delete topElement;
topElement = tempAdr;
NumberOfElements--;
}
}
T top(){
return NumberOfElements != 0 ? topElement->element : throw STACK_EMPTY;
}
void insert(size_t position, T input_element){
if (position >= NumberOfElements) throw OUT_OF_STACK;
else {
tempAdr = topElement;
for (size_t i = 0; i < position; i++){
tempAdr = tempAdr->prevElement;
}
newElement = new Node;
newElement->element = input_element;
newElement->prevElement = tempAdr->prevElement;
tempAdr->prevElement = newElement;
NumberOfElements++;
}
}
void erase(size_t position){
if (position >= (NumberOfElements-1)) throw OUT_OF_STACK;
else{
tempAdr = topElement;
for (size_t i = 0; i < position; i++){
tempAdr = tempAdr->prevElement;
}
erasedElement = tempAdr->prevElement;
tempAdr->prevElement = tempAdr->prevElement->prevElement;
delete erasedElement;
NumberOfElements--;
}
}
void print(){
if (NumberOfElements != 0){
tempAdr = topElement;
for (size_t i = 0; i < NumberOfElements; i++){
cout << tempAdr->element << " ";
tempAdr = tempAdr->prevElement;
}
}
}
size_t size() { return NumberOfElements; }
};
vector<int> ReadTheFile() {
vector<int> vec_from_file;
int buffer;
ifstream basefile;
basefile.open("num_file.txt", ios::in);
if (basefile.is_open()) {
do {
if (basefile >> buffer)
vec_from_file.push_back(buffer);
else {
basefile.clear();
basefile.ignore(1, ' ');
}
} while (!basefile.eof());
basefile.close();
}
else cout << "Unable to open file" << endl;
return vec_from_file;
}
vector<int> IntervalCheck(vector<int> vec_for_check){
vector<int> out_vec;
if (vec_for_check.empty()) cout << "There is nothing to check";
else {
int begin_int, end_int;
do {
cin.clear();
cin.sync();
cout << "Input the first and the last value of the interval: ";
cin >> begin_int >> end_int;
} while (cin.fail());
for (auto &k : vec_for_check)
if (k > begin_int && k < end_int)
out_vec.push_back(k);
}
return out_vec;
}
Stack<int> VecToMyStack(vector<int> input_vec){
Stack<int> output_st;
if (input_vec.empty()) {
cout << "the end";
}
else {
for (auto &k : input_vec){
output_st.push(k);
}
}
return output_st;
}
int main(){
int choice = 0;
do {
cin.clear();
cin.sync();
VecToMyStack(IntervalCheck(ReadTheFile())).print();
cout << "Would you like to measure another interval? 1-yes 2-no";
cin >> choice;
} while (choice == 1);
system("pause");
return 0;
}
整个程序应该将数字从文件推送到堆栈,并使用类的print()
方法打印此堆栈。例如,如果有num_file.txt
0 1 2 3 4 5 6 7 8 9 10
在内部,该计划预计将以这种方式运作:
但是当执行VecToMyStack(IntervalCheck(ReadTheFile())).print();
行时,我正在
访问冲突读取位置0xFEEEFEEE。
异常。它似乎像我的Stack类的析构函数在print()
函数之前运行。为什么会这样?我应该在Stack类或VecToMyStack()
函数中添加一些特殊内容吗?
答案 0 :(得分:0)
最后,经过几个小时的研究,我发现错过了代码的和平:
Stack(const Stack &object){
tempAdr = object.topElement;
T * tempMas=new T[object.NumberOfElements];
for (size_t i = 0; i < object.NumberOfElements; i++){
tempMas[i] = tempAdr->element;
tempAdr = tempAdr->prevElement;
}
topElement = new Node;
topElement->prevElement = nullptr;
NumberOfElements = 0;
for (int i = object.NumberOfElements - 1; i >= 0; i--){
push(tempMas[i]);
}
delete[] tempMas;
}
我知道没有重载赋值运算符,我的Stack类仍然不完整,但至少我的代码运行正常。