Question

现在我正在努力在屏幕上制作Python“类型”（我感到无聊和实验性），而且我自己得到了这么多，但我找不到任何方法在我的脚本中使用小数因为Python只接受randint（）的整数。

#include <stdio.h>;
import sys;
import time;
import os;
import random;
os.system("clear");

script = "I just really need to type something right now. I'm not sure why, but I really feel like typing on the Chromebook right now. It seems kinda weird, but I like doing this. It helps me practice what I'm doing. I've noticed that I'm a lot worse at typing lately, and I don't know why. Maybe it's because I've been working with a chunky keyboard, and these Chromebook keyboards are extremely thin. Yup, this is actually entertaining for me. I'm not exactly sure why I want to do this, but I just do. It's almost addicting to me, and I don't know why.\n";

for i in range(0, 587):
sys.stdout.write(str(scripti));
sys.stdout.flush();
time_num = random.randint(0.1, 0.4);
time.sleep(time_num);

我得到的输出是：

ITraceback (most recent call last):
File "main.py", line 11, in <module>
time_num = random.randint(0.1, 0.4);
File "/usr/lib64/python2.7/random.py", line 242, in randint
return self.randrange(a, b+1)
File "/usr/lib64/python2.7/random.py", line 187, in randrange
raise ValueError, "non-integer arg 1 for randrange()"
ValueError: non-integer arg 1 for randrange()

有什么想法吗？

编辑：不要告诉我如何使这更简单，因为这只是为了学习。

Answer 1

为什么不使用随机均匀分布？在这种情况下，您可以获得非整数值。使用：

import random
random.uniform(0.1,0.4)

Answer 2

如果您使用randint，则可以执行time_num = randint(1, 4)/10。

Answer 3

for i in range(0, 587):

......没有任何东西在那里缩进（除非你没有在问题中发布缩进）..所以它实际上无用

对于time_num变量，您可以像这样投射它：

time_num = double(random.randrange(1, 4) \ 10

你必须尝试在milliseconds中获取它，因为python使用Second time import

但您也可以改为使用randint使用random.randrange(#1, #2)

我不知道sys import但您使用了这个 - ＆gt; sys.stdout.write(str(scripti));

但是您的变量名为"script" .........

生成随机浮点数

3 个答案: