Question

我正在试图弄清楚是否可以在ExpandableListView中启动一个intent。基本上其中一个“组”是电话号码，其子号码是号码。我希望用户能够单击它并让它自动调用该号码。这可能吗？怎么样？

这是我使用名为“data”的Map填充ExpandableListView的代码。

ExpandableListView myList = (ExpandableListView) findViewById(R.id.myList);
                //ExpandableListAdapter adapter = new MyExpandableListAdapter(data);
                List<Map<String, String>> groupData = new ArrayList<Map<String, String>>();
                List<List<Map<String, String>>> childData = new ArrayList<List<Map<String, String>>>();

                Iterator it = data.entrySet().iterator();
                while (it.hasNext()) 
                {
                    //Get the key name and value for it
                    Map.Entry pair = (Map.Entry)it.next();
                    String keyName = (String) pair.getKey();
                    String value = pair.getValue().toString();

                    //Add the parents -- aka main categories
                    Map<String, String> curGroupMap = new HashMap<String, String>();
                    groupData.add(curGroupMap);
                    curGroupMap.put("NAME", keyName);

                    //Add the child data
                    List<Map<String, String>> children = new ArrayList<Map<String, String>>();
                    Map<String, String> curChildMap = new HashMap<String, String>();
                    children.add(curChildMap);
                    curChildMap.put("NAME", value);

                    childData.add(children);

                }

                // Set up our adapter
                mAdapter = new SimpleExpandableListAdapter(
                        mContext,
                        groupData,
                        R.layout.exp_list_parent,
                        new String[] { "NAME", "IS_EVEN" },
                        new int[] { R.id.rowText1, R.id.rowText2  },
                        childData,
                        R.layout.exp_list_child,
                        new String[] { "NAME", "IS_EVEN" },
                        new int[] { R.id.rowText3, R.id.rowText4}
                        );

                myList.setAdapter(mAdapter);

Answer 1

您可以在展开式列表视图中添加OnChildClickListener。当调用OnChildClick时，您具有组和子位置，因此您应该能够确定单击了哪个电话号码。

然后你只需要发出拨打电话的意图，即：

Intent intent = new Intent(Intent.CALL_ACTION);
intent.setData(Uri.parse("tel:+436641234567"));
startActivity(intent);

Android - 在ExpandableListView中启动Intent

1 个答案: