Question

我遇到了如何在浏览器上显示网址链接的问题。

下面是我的servlet文件和jsp文件。

Search.java：

   import java.io.IOException;
   import javax.servlet.*;
   import javax.servlet.http.*;
   import java.sql.PreparedStatement;
   import java.sql.ResultSet;
   import java.sql.SQLException;
   import java.sql.Statement;
   import org.jsoup.Jsoup; 
   import org.jsoup.nodes.Document;
   import org.jsoup.nodes.Element;
   import org.jsoup.select.Elements;
   import java.io.PrintWriter;

   public class Search extends HttpServlet 
   {

    private static final long serialVersionUID = 1L;
    public static DB db = new DB();

     protected void doGet(HttpServletRequest request,HttpServletResponse 
       response) throws ServletException, IOException 

   {
        PrintWriter out=response.getWriter();



       try {
           db.runSql2("TRUNCATE Record;");
       } 
    catch (SQLException e) {
           // TODO Auto-generated catch block
           e.printStackTrace();
       }
        try {
           processPage("http://www.yahoo.com");
        } 
           catch (SQLException e) {
            // TODO Auto-generated catch block
           e.printStackTrace();
       }
    }   

       public static void   processPage(String URL) throws SQLException,
          IOException
    {
        //check if the given URL is already in database
    String sql = "select * from Record where URL = '"+URL+"'";
    ResultSet rs = db.runSql(sql);
    if(rs.next())

    {

    }
    else
    {
         //store the URL to database to avoid parsing again
            sql = "INSERT INTO  `tenderMysql`.`Record` " + "(`URL`) 
    VALUES " + "(?);";
        PreparedStatement stmt = db.conn.prepareStatement(sql, 
          Statement.RETURN_GENERATED_KEYS);
           stmt.setString(1, URL);
           stmt.execute();

           //get useful information
           Document doc = Jsoup.connect("http://www.yahoo.com").get();

           if(doc.text().contains("crash")){
                System.out.println(URL);
           }

           //get all links and recursively call the processPage method
           Elements questions = doc.select("a[href]");
            for(Element link: questions)
           {
                if(link.attr("href").contains("www"))
                   processPage(link.attr("abs:href"));
           }
       }
    }

  }

下面给出的是我的jsp文件，我必须在浏览器上显示链接。

Search.jsp：

    <%@ page language="java" contentType="text/html; charset=ISO-8859-1"  
    pageEncoding="ISO-8859-1"%>
 <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" 
     "http://www.w3.org/TR/html4/loose.dtd">
  <html>
  <head>
      <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
 <title>
 Select website name from DropdownList
 </title>  
       </head>
    <body bgcolor="8B4513">
   <form  action="HelloServlet" >
    <center>
   <h1> Optimzed Search</h1>
  <br>
  </center>
 </form>
  </body>   
  </html>

Answer 1

如果你想在普通的html页面上打印出来，你可以写出来。

 protected void doGet(...)
 {
   PrintWriter out=response.getWriter();
   processPage("http://www.yahoo.com", out);
 }    

public static void   processPage(String URL, PrintWriter out)
{
   ....
   if(doc.text().contains("crash")){
       out.println("<p>" + URL+ "</p>");
    }
}

将依赖jar添加到eclipse中的部署资源列表：

project -- > properties --> Deployment Assembly -- > Add - 
-> Archive from File system ---> Add --> Select your jar (in this case soup)

如何在浏览器中显示Url链接而不是在java中显示控制台

1 个答案: