注意:我想知道downvote的原因。我认为这是一个非常合理的问题,格式正确。我并不真正关心选票,因为我只是在这里学习,但是没有任何解释而给予downvote的人会阻止很多人提问和学习。
我在下面写了一个从webservice获取json的代码,当我在一个新的单一视图项目中运行它时工作正常#34;但是当我在项目中添加它时,它会出现**fatal error: unexpectedly found nil while unwrapping an Optional value**
错误。您还可以从下面的屏幕截图中看到它出错的地方。
代码:
import UIKit
class NewsViewController: UIViewController {
@IBOutlet var newsTableView: UITableView!
var newsTitles : NSMutableArray = NSMutableArray() // will contain news contents from API
var newsURLs : NSMutableArray = NSMutableArray() // will contain news URLs from API
var newsResponse : NSMutableArray = NSMutableArray() // will contain server response
override func viewDidLoad() {
super.viewDidLoad()
getNews()
}
override func didReceiveMemoryWarning() {
super.didReceiveMemoryWarning()
// Dispose of any resources that can be recreated.
}
// Calling News Service
func getNews(){
var serviceParam: AnyObject = NSUserDefaults.standardUserDefaults().objectForKey("key4news")!
var apiURL = "http://myIP/myWebService?search_text=\(serviceParam)"
println(apiURL)
var request : NSMutableURLRequest = NSMutableURLRequest()
request.URL = NSURL(string: apiURL)
request.HTTPMethod = "GET"
NSURLConnection.sendAsynchronousRequest(request, queue: NSOperationQueue(), completionHandler:{ (response:NSURLResponse!, data: NSData!, error: NSError!) -> Void in
var error: AutoreleasingUnsafeMutablePointer<NSError?> = nil
let jsonResult: NSDictionary! = NSJSONSerialization.JSONObjectWithData(data, options:NSJSONReadingOptions.MutableContainers, error: error) as? NSDictionary
if (jsonResult != nil) {
self.newsResponse = jsonResult.objectForKey("result") as NSMutableArray
for var i=0; i<self.newsResponse.count; i++ {
self.newsTitles[i] = self.newsResponse[i].objectForKey("title")! as NSString
self.newsURLs[i] = self.newsResponse[i].objectForKey("link")! as NSString
println("news title: \(self.newsTitles[i])")
println("news link: \(self.newsURLs[i])")
println("\n\n")
}
} else {
// couldn't load JSON, look at error
println("jsonResult is nil")
}
})
}
func tableView(tableView:UITableView!, numberOfRowsInSection section:Int) -> Int
{
return 10
}
func tableView(tableView: UITableView!, cellForRowAtIndexPath indexPath: NSIndexPath!) -> UITableViewCell!
{
let cell:UITableViewCell=UITableViewCell(style: UITableViewCellStyle.Subtitle, reuseIdentifier: "newsItem")
cell.textLabel?.text = newsTitles[indexPath.row] as NSString
return cell
}
func tableView(tableView: UITableView!, didSelectRowAtIndexPath indexPath: NSIndexPath!) {
println("you've touched tableviewcell")
}
/*
// MARK: - Navigation
// In a storyboard-based application, you will often want to do a little preparation before navigation
override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
// Get the new view controller using segue.destinationViewController.
// Pass the selected object to the new view controller.
}
}
这是我的网络服务的JSON格式(它返回&#39;结果&#39;数组中的最多10个项目):
{
"status": "ok",
"result": [
{
"date added": "2014-12-29 00:00:00",
"link": "http:link3.com",
"description": "description of first news",
"title": "title of first news"
},
{
"date added": "2013-10-15 00:00:00",
"link": "http:link3.com",
"description": "description of second news",
"title": "title of second news"
},
{
"date added": "2013-04-09 00:00:00",
"link": "http:link3.com",
"description": "description of third news",
"title": "title of third news"
}
]
}
我该如何解决这个问题?
答案 0 :(得分:2)
我认为您没有从服务器获取数据作为响应,这就是导致此错误的原因。
您需要进行网址编码。
您的代码
var serviceParam: AnyObject = NSUserDefaults.standardUserDefaults().objectForKey("key4news")!
var apiURL = "http://myIP/myWebService?search_text=\(serviceParam)"
需要像
var serviceParam: AnyObject = NSUserDefaults.standardUserDefaults().objectForKey("key4news")!
serviceParam = serviceParam.stringByAddingPercentEncodingWithAllowedCharacters(.URLHostAllowedCharacterSet())!
var apiURL = "http://myIP/myWebService?search_text=\(serviceParam)"