基于java中的另一个结果集调整结果集
我有四种方法，两种方法，即 FindClosestToMultiplesOfTen（）和ClosestToMultiplesOfTen_User（）通过用户给出对应于输入的logtime 的beam_current值。其他两种方法检索全部这些beam_current上的其他字段。 我认为从FindClosestToMultiplesOfTen检索的beam_current作为参考beam_current，它们被传递到另一个方法，即refernece（）方法，并检索与其对应的其他值。用其他两种方法完成类似的事情，即ClosestToMultiplesOfTen_User，并将来自它的beam_current值传递给refarray_vac1.Now我计算从这两种方法中获得的值的差异，并通过jsp apge显示它们。
Problem-
1）我希望从refarray_vac1（）方法中检索到的与beam_current相对应的所有值都应该直接位于refernece（）的相应值下面。
到目前为止获得的输出是 -
在这里，您可以看到以浅色显示的行来自refarray_vac1，并将它们与以灰色显示的行进行比较。这里接近10的值表示在10的参考行下面，但是我希望它在参考的20.02行以下表示，并且null应该在灰色10行以下表示，因为在浅色10值中缺失。然后所有的行都会到来低于相应的行。
方法代码是
public LinkedHashMap<Double, String> FindClosestToMultiplesOfTen(String name) throws SQLException {
int row_id ;
int bIdx = 0;
//double[] vals = new double[47];
double[] vals=null;
//double[] bucket =new double[22];
int rowIndex = 0 ;
int i=0;
String first=name.substring(1,19);
String last =name.substring(24,42);
try
{
con = getConnection();
stmt = con.createStatement(ResultSet.TYPE_SCROLL_SENSITIVE,ResultSet.CONCUR_READ_ONLY);
String sql="select distinct beam_current from INDUS2_BDS.dbo.DCCT where logtime between '"+first+"' and '"+last+"'"+
"and (beam_current like '%9.95' or beam_current like '%9.96' or beam_current like '%9.97' or beam_current like '%9.98' or beam_current like '%9.99' or beam_current like '%0' or beam_current like '%_0.01' or beam_current like '%_0.02' or beam_current like '%_0.03' or beam_current like '%_0.04' or beam_current like '%_0.05' or beam_current like '%_0.06')";
System.out.println("Value of sql of FindClosestToMultiplesOfTen is"+sql);
stmt.executeQuery(sql);
rs = stmt.getResultSet();
rs.last();
int row_cnt=rs.getRow();
System.out.println("row_count of closest " +row_cnt);
vals = new double[row_cnt];
rs.beforeFirst();
while(rs.next())
{
for(int j=0; j<1; j++)
{
vals[i] = rs.getDouble(1);
}
i++;
}
}
catch( Exception e )
{
System.out.println("\nException "+e);
}
// get the max value, and its multiple of ten to get the number of buckets
double max = java.lang.Double.MIN_VALUE;
for (double v : vals)
{
System.out.println("value of v after double v : vals"+v);
max = Math.max(max, v);
}
Arrays.sort(vals);
System.out.println("Min value in array in c "+vals[0]);
double min=vals[0];
int m2=(int) Math.round(min);
int m3=(int) Math.round(max);
int bucketCount = 1+((m3-m2)/10);
double[] bucket =new double[bucketCount];
// initialise the buckets array to store the closest values
double[][] buckets = new double[bucketCount][3];
for (int i1 = 0; i1 < bucketCount; i1++){
// store the current smallest delta in the first element
buckets[i1][0] = java.lang.Double.MAX_VALUE;
// store the current "closest" index in the second element
buckets[i1][1] = -1d;
// store the current "closest" value in the third element
buckets[i1][2] = java.lang.Double.MAX_VALUE;
}
// iterate the rows
for (row_id=0 ; row_id < vals.length; row_id++) // row_id=137
{
// get the value from the row
double v = vals[row_id];
// get the closest multiple of ten to v
double mult = getMultipleOfTen(v); // e.g. 50, 60, etc
// get the absolute distance of v from the multiple of ten
double delta = Math.abs(mult - v); // 50 - 49.9 = 0.1
// get the bucket index based on the value of `mult`
bIdx = (int)(mult / 10d) - m2/10;//50/10=5
if (buckets[bIdx][0] > delta) // max>0.1
{
buckets[bIdx][0] = delta;//.01(50-49.95)
buckets[bIdx][1] = row_id;
buckets[bIdx][2] = v;
System.out.println("beam_current: "+buckets[bIdx][2]);
//z++;
}
}
System.out.format(" 10x row value%n");
for (int i1 =0; i1 < buckets.length; i1++)
{
bucket = buckets[i1];
rowIndex = (int) bucket[1];
int row_no=rowIndex+1;
double rowValue = bucket[2];
System.out.println("row index "+row_no+ "value is "+rowValue);
DecimalFormat twoDForm = new DecimalFormat("#.##");
rs.absolute(rowIndex+1);
map1.put(java.lang.Double.valueOf(twoDForm.format(rs.getDouble(1))),"");
}
return map1;
}
在FindClosestToMultiplesOfTen（）和ClosestToMultiplesOfTen_User（）方法中，只有结果集的大小不同，因为两者的logtime不同。现在我想要ClosestToMultiplesOfTen_User（）结果集的大小等于FindClosestToMultiplesOfTen的结果集大小，null应该放在处理后得到的ClosestToMultiplesOfTen_User的结果集中没有对应值的地方。
ClosestToMultiplesOfTen_User的代码是 -
public LinkedHashMap<Double, String> ClosestToMultiplesOfTen_User(String start,String end) throws SQLException {
int row_id ;
int bIdx = 0;
double[] vals=null;
int rowIndex = 0 ;
int i=0;
try
{
con = getConnection();
stmt = con.createStatement(ResultSet.TYPE_SCROLL_SENSITIVE,ResultSet.CONCUR_READ_ONLY);
String sql="select distinct beam_current from INDUS2_BDS.dbo.DCCT where logtime between '"+start+"' and '"+end+"'"+
"and (beam_current like '%9.95' or beam_current like '%9.96' or beam_current like '%9.97' or beam_current like '%9.98' or beam_current like '%9.99' or beam_current like '%0' or beam_current like '%_0.01' or beam_current like '%_0.02' or beam_current like '%_0.03' or beam_current like '%_0.04' or beam_current like '%_0.05' or beam_current like '%_0.06') ";
System.out.println("Value of sql of FindClosestToMultiplesOfTen is"+sql);
stmt.executeQuery(sql);
rs = stmt.getResultSet();
rs.last();
int row_cnt=rs.getRow();
System.out.println("row_count of closest " +row_cnt);
vals = new double[row_cnt];
rs.beforeFirst();
while(rs.next())
{
for(int j=0; j<1; j++)
{
vals[i] = rs.getDouble(1);
}
i++;
}
}
catch( Exception e )
{
System.out.println("\nException "+e);
}
// get the max value, and its multiple of ten to get the number of buckets
double max = java.lang.Double.MIN_VALUE;
for (double v : vals) max = Math.max(max, v);
Arrays.sort(vals);
System.out.println("value at vals[0] c "+vals[0]);
double min=vals[0];
int m2=(int) Math.round(min);
int m3=(int) Math.round(max);
int bucketCount = 1+((m3-m2)/10);
double[] bucket =new double[bucketCount];
System.out.println("bucketcount in closest "+bucketCount);
// initialise the buckets array to store the closest values
double[][] buckets = new double[bucketCount][3];
for (int i1 = 0; i1 < bucketCount; i1++){
// store the current smallest delta in the first element
buckets[i1][0] = java.lang.Double.MAX_VALUE;
// store the current "closest" index in the second element
buckets[i1][1] = -1d;
// store the current "closest" value in the third element
buckets[i1][2] = java.lang.Double.MAX_VALUE;
}
// iterate the rows
for (row_id=0 ; row_id < vals.length; row_id++)
{
// get the value from the row
double v = vals[row_id];
System.out.println("value at "+row_id+": "+v);
// get the closest multiple of ten to v
double mult = getMultipleOfTen(v);
// get the absolute distance of v from the multiple of ten
double delta = Math.abs(mult - v);
// get the bucket index based on the value of `mult`
bIdx = (int)(mult / 10d) - m2/10;
if (buckets[bIdx][0] > delta)
{
// this is closer than the last known "smallest delta"
buckets[bIdx][0] = delta;
buckets[bIdx][1] = row_id;
buckets[bIdx][2] = v;
System.out.println("beam_current closeset: "+buckets[bIdx][2]);
}
}
// print out the result
for (int i1 =0; i1 < buckets.length; i1++)
{
bucket = buckets[i1];
rowIndex = (int) bucket[1];
double rowValue = bucket[2];
//System.out.println("row index "+row_no+ "value is "+rowValue);
DecimalFormat twoDForm = new DecimalFormat("#.##");
System.out.println("row index closeset "+rowIndex+ "value is closest "+rowValue);
//System.out.println("value of rowIndex+1 is"+row_no);
rs.absolute(rowIndex+1);
user_current_map.put(java.lang.Double.valueOf(twoDForm.format(rs.getDouble(1))),"");
// map1.put(rs.getString(2),(rs.getString(1)));
//l.add(map1);
}
System.out.println("user_current_map "+user_current_map);
return user_current_map;
}
refarray_vac1（）的代码是
public List<Vacc1_Decline> refarray_vac1(String fdate,String ldate) throws SQLException, ParseException {
st_jsp.clear();
//System.out.println("date from jsp is : "+date);
List<Double> slist_user = new ArrayList<Double>(user_current_map.keySet());
String s_user = StringUtils.join(slist_user, ',');
System.out.println("comma separated string by user_selection" +s_user);
// int i=0;
try
{
con = getConnection();
stmt = con.createStatement(ResultSet.TYPE_SCROLL_SENSITIVE,ResultSet.CONCUR_READ_ONLY);
String vs1= " sql query";
// System.out.println("value from user_selection is " +vs1);
stmt.executeQuery(vs1);
rs = stmt.getResultSet();
while (rs.next()) {
Vacc1_Decline ref = new Vacc1_Decline();
ref.setLogtime(rs.getString(1));
ref.setBeam_current(rs.getString(2));
ref.setBeam_energy(rs.getString(3));
ref.setSt1_vs1_bag1_rb(rs.getString(4));
ref.setSt1_vs1_bag2_rb(rs.getString(5));
st_jsp.add(ref);
}
}
catch( Exception e )
{
System.out.println("\nException in refarray_vac1 "+e);
}
return st_jsp;
}
0 个答案:
没有答案
相关问题
最新问题
- 我写了这段代码，但我无法理解我的错误
- 我无法从一个代码实例的列表中删除 None 值，但我可以在另一个实例中。为什么它适用于一个细分市场而不适用于另一个细分市场？
- 是否有可能使 loadstring 不可能等于打印？卢阿
- java中的random.expovariate()
- Appscript 通过会议在 Google 日历中发送电子邮件和创建活动
- 为什么我的 Onclick 箭头功能在 React 中不起作用？
- 在此代码中是否有使用“this”的替代方法？
- 在 SQL Server 和 PostgreSQL 上查询，我如何从第一个表获得第二个表的可视化
- 每千个数字得到
- 更新了城市边界 KML 文件的来源？