用于在透视行中显示日期计数的php代码

Question

数据存在我的数据库中，如下所示......

COLUMNNAME surveyor_name -varchar

bookingdate - varchar

receipt_no - varchar

surveyor   bookingdate     receipt_no

 raj       19-03-2015        55
 raj       19-03-2015        55
 raj       19-03-2015        55
 raj       19-03-2015        55
 raj       19-03-2015        55
 raj       19-03-2015        55

 raj       19-03-2015        56
 raj       19-03-2015        56
 raj       19-03-2015        56
 raj       19-03-2015        56
 raj       19-03-2015        56
 raj       19-03-2015        56

sudnyesh    20-03-2015       700
sudnyesh    20-03-2015       700
sudnyesh    20-03-2015       700
sudnyesh    20-03-2015       700
sudnyesh    20-03-2015       700
sudnyesh    20-03-2015       700

angel       24-03-2015        702
angel       24-03-2015        702
angel       24-03-2015        702
angel       24-03-2015        702
angel       24-03-2015        702
angel       24-03-2015        702

预期输出

 surveyor name  19-03-2015    20-03-2015   24-03-2015
  angel                                        1
  raj             2            
  sudnyesh                       1

但我的代码显示输出如下......

surveyor name  19-03-2015    20-03-2015   24-03-2015
  angel            1                            1
  raj             2             2
  sudnyesh                       1              1

任何人都可以帮我显示正确的输出。

下面是我的代码。

FOR EX - 在我的预期输出中....

raj在19-03-2015创建了2张收据55,56，因此我们在19-03-2015以下的raj前面显示总共2张

sudnyesh在20-03-2015创建了1张收据700，因此我们在20-03-2015以下的sudnyesh前面显示总共1张......

请帮我实现这个目标..

<?php $book = $database->getRows("SELECT DISTINCT bookingdate FROM receipt_entry"); ?>
<?php $data = $database->getRows("select surveyor_name, count(DISTINCT receipt_no) As total,bookingdate from receipt_entry group by surveyor_name,bookingdate");  ?>
<table border="1px solid #666" style="text-align:center;" cellpadding='0' cellspacing='0'>
<thead>
    <tr>
        <th>Surveyor Name</th>
        <?php foreach($book as $date):?>
            <?php $dates[] = $date['bookingdate'];?>
            <th><?php echo $date['bookingdate'];?></th>
        <?php endforeach;?>
    </tr>
</thead>
<tbody>
    <?php $j = 0;?>
    <?php foreach($data as $key => $value):?>
        <?php $names[] = $value['surveyor_name'];?>
        <?php $uniValues = array_count_values($names);?>
        <?php if($uniValues[$value['surveyor_name']] == 1):?>
        <tr>
            <td>
                <?php echo $value['surveyor_name'];?>
            </td>
            <?php $i = 0;?>
            <?php foreach($book as $date):?>
                <td align="center">
                    <?php if($names[$i] == $data[$j]['surveyor_name']):?>
                        <?php echo $data[$j]['total'];?>
                    <?php else:?>
                        <?php foreach($data as $dat):?>
                            <?php if($dat['surveyor_name'] == $names[$j] && $dates[$i] == $dat['bookingdate']):?>
                                <?php echo $dat['total'];?>
                            <?php endif;?>
                        <?php endforeach;?>
                    <?php endif;?>
                </td>
                <?php ++$i;?>
            <?php endforeach;?>
        </tr>
        <?php endif;?>
        <?php ++$j;?>
    <?php endforeach;?>
</tbody>
</table>