我有一个WPF项目,我在Windows中添加了一个框架,框架的来源是页面。我想点击页面中的一个按钮来改变框架的页面。
<Window x:Class="MagicArm.MainWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:local="clr-namespace:MagicArm"
Title="MainWindow">
<Frame Name="FrameContent"Source="PageStart.xaml"></Frame>
</Window>
PageStart:
<Page x:Class="MagicArm.PageStart"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
mc:Ignorable="d"
Height="452" Width="800"
Title="PageStart">
<Canvas>
<button name=""> </button>
</Canvas>
答案 0 :(得分:7)
编辑:功能解决方案可能如下所示:
MainWindow XAML:
<StackPanel>
<Frame Name="frmMainContent" Height="260"
DataContext="MyPageInformation"
Source="{Binding}"
NavigationUIVisibility="Hidden">
</Frame>
</StackPanel>
MainWindow cs:
frmMainContent.Source = new Uri("test1.xaml", UriKind.Relative); // initialize frame with the "test1" view
test1 XAML:
<Grid>
<Button Click="ButtonBase_OnClick" Background="Red" Height="30" Width="100">Go to page 2</Button>
</Grid>
test1 cs:
private void ButtonBase_OnClick(object sender, RoutedEventArgs e)
{
NavigationService ns = NavigationService.GetNavigationService(this);
ns.Navigate(new Uri("test2.xaml", UriKind.Relative));
}
test2 XAML:
<Grid>
<Button Click="ButtonBase_OnClick" Width="100" Height="30" Background="RoyalBlue"> Go to page 1</Button>
</Grid>
test2 cs:
NavigationService ns = NavigationService.GetNavigationService(this);
ns.Navigate(new Uri("test1.xaml", UriKind.Relative));
这是一个使用NavigationService的工作解决方案。