Question

删除＆＃34; n＆＃34;匹配模式后面的行很容易使用：

IFM_MOUNT="/opt/insiteone/fuse-mount2/ifm"
sed -i "\|$IFM_MOUNT|,+6 d" smb.conf (deletes lines matching and next 6 lines)

但我的问题是，我希望删除匹配模式之前的2行。

如何实现？我将调用该命令的文件是Samba配置文件，如下所示：

[DCCAArchive1]
        comment = DCCA Archive File System
        path = /opt/insiteone/fuse-mount1/ifm
        read only = No
        public = yes
        case sensitive = yes
        writable = yes
        create mask=0777
        guest ok = Yes

[DCCAArchive2]
        comment = DCCA Archive File System
        path = /opt/insiteone/fuse-mount2/ifm
        read only = No
        public = yes
        case sensitive = yes
        writable = yes
        create mask=0777
        guest ok = Yes

[DCCAArchive3]
        comment = DCCA Archive File System
        path = /opt/insiteone/fuse-mount3/ifm
        read only = No
        public = yes
        case sensitive = yes
        writable = yes
        create mask=0777
        guest ok = Yes

Answer 1

正如我评论的那样，如果格式是固定的（数据块之间的空行），这一行就可以完成这项任务：

awk -v RS="" '!/PATTERN/' input

如果不是这种情况，你可以试试这个awk one-liner：

awk '{a[NR]=$0}/PATTERN/{for(i=NR-2;i<=NR+6;i++)d[i]=1}
     END{for(i=1;i<=NR;i++)if(!d[i])print a[i]}' input

测试

将ifm简化为PATTERN
“数据块”之间没有空行

遵循您的规则：删除行hit-2 -> hit+6

kent$  cat f
fooooooooo
[DCCAArchive1]
        comment = DCCA Archive File System
        path = /opt/insiteone/fuse-mount1/ifm
        read only = No
        public = yes
        case sensitive = yes
        writable = yes
        create mask=0777
        guest ok = Yes
barrrrrrrrrrrr
[DCCAArchive2]
        comment = DCCA Archive File System
        path = /opt/insiteone/fuse-mount2/ifm
        read only = No
        public = yes
        case sensitive = yes
        writable = yes
        create mask=0777
        guest ok = Yes

kent$  awk  '{a[NR]=$0}/ifm/{for(i=NR-2;i<=NR+6;i++)d[i]=1}END{for(i=1;i<=NR;i++)if(!d[i])print a[i]} ' f
fooooooooo
barrrrrrrrrrrr

修改

使用shell变量中的模式：

kent$  PAT="/fuse-mount2/ifm"

kent$  awk -v p="$PAT" '{a[NR]=$0}{if(match($0,p)>0){for(i=NR-2;i<=NR+6;i++)d[i]=1}}END{for(i=1;i<=NR;i++)if(!d[i])print a[i]} ' f                                          
fooooooooo
[DCCAArchive1]
        comment = DCCA Archive File System
        path = /opt/insiteone/fuse-mount1/ifm
        read only = No
        public = yes
        case sensitive = yes
        writable = yes
        create mask=0777
        guest ok = Yes
barrrrrrrrrrrr

Answer 2

您使用以下sed命令：

sed -r ':a;N;s~([^\n]*\n){2}[^\n]*'"$search"'\n~~;ba' file

该命令基本上作为循环工作。 :a标记循环开始处的标签。 N读取下一行输入并将其附加到模式缓冲区。 s~([^\n]+\n){2}PATTERN\n~~将删除模式，并在其前面删除两行。请注意，我使用~作为分隔符，因为输入数据包含“标准”分隔符/。 ba将分支回到循环的开头。在输入结束时，修改后的文件将被打印$p。

顺便说一句，只需将搜索模式中的2更改为您想要的任何内容，即可将模式更改为任意数量的前一行。

sed - 删除匹配模式之前和之后的n行

2 个答案:

修改