@Lalue在insert语句中使用时得到了正确的值。但是,当使用php调用此存储过程时,@ AID(设置为@Value)始终为0。
ALTER PROCEDURE [dbo].[UpdateActivity2]
@ParentActivity int,
@ActivityName varchar(150),
@ActivityType int,
@ActivityStatus int,
@Descr varchar(1024),
@RegistrationDate datetime,
@FinishDate datetime,
@Owner int,
@SourceID int,
@ContactID int,
@ActivityAddress varchar(150),
@ExtReference varchar(50),
@ResponsibleCompanyID int,
@AID int OUTPUT
AS
BEGIN
DECLARE @Value int;
EXEC @Value = PG_GetSeq @Name = 'Activity'
INSERT INTO Activity(
ActivityID,
ParentActivity,
ActivityName,
ActivityType,
ActivityStatus,
Descr,
RegistrationDate,
FinishDate,
Owner,
SourceID,
ContactID,
ActivityAddress,
ExtReference,
ResponsibleCompanyID
)
VALUES(
@Value,
@ParentActivity,
@ActivityName,
@ActivityType,
@ActivityStatus,
@Descr,
@RegistrationDate,
@FinishDate,
@Owner,
@SourceID,
@ContactID,
@ActivityAddress,
@ExtReference,
@ResponsibleCompanyID
)
SELECT @AID = @Value
END
我在这里做错了什么?它与在另一个存储过程中调用存储过程有关吗?