访问动态添加的元素

Question

var $singleMember = '<a class="singleMember"><img class="avatar"><p class="username"></p></a>';

$singleMember.attr('href',member.link);
$singleMember.children('.avatar').attr('src',member.avatar);
$singleMember.children('.username').html(member.name);

为什么抛出＆＃34; undefined不是函数＆＃34;？

Answer 1

var $singleMember只是一个字符串，因此.attr()和.children()无效（因此您看到错误）

将其切换为：

   var singleMember = '<a class="singleMember"><img class="avatar"><p    class="username"></p></a>';
   var $singleMember = $(singleMember);

   $singleMember.attr('href',member.link);
   $singleMember.children('.avatar').attr('src',member.avatar);
   $singleMember.children('.username').html(member.name);