考虑到用户区域设置,如何将段落中每个句子的第一个单词大写?我想要实现的是无论句子里面的情况如何,每个单词的第一个字母都是大写的,其余的都是小写的。首先将所有内容转换为小写,然后获得第一个字母并制作大写字母,最后将它们加在一起,我只能做一个句子。我的问题与How to capitalize each word in a string using Swift iOS不同,因为我不想将每个单词都大写。我只想把每个句子的第一个单词弄清楚。 capitalizedString
转
"this is first sentence. this is second sentence."
到
"This Is First Sentence. This Is Second Sentence."
我想要的是
"This is first sentence. This is second sentence."
我的问题也与Capitalise first letter of every sentence不同,因为@ rintaro的代码不适用于我的下面的例子。它保留原始文本中的大写字母完整。使用@ rintaro的代码;
前
"someSentenceWith UTF text İŞğĞ. anotherSentenceğüÜğ"
后
"SomeSentenceWith UTF text İŞğĞ. AnotherSentenceğüÜğ."
我想要实现的目标,
"Somesentencewith utf text işğğ. Anothersentenceğüüğ."
我的代码只能进行部分转换。
var description = "someSentenceWith UTF text İŞğĞ. anotherSentenceğüÜğ"
description = description.lowercaseStringWithLocale(NSLocale.currentLocale())
let first = description.startIndex
let rest = advance(first,1)..<description.endIndex
let capitalised = description[first...first].uppercaseStringWithLocale(NSLocale.currentLocale()) + description[rest]
如果您能仔细阅读我的问题,我将非常感谢,因为这是我第三次编辑这个问题。如果我不能清楚地问清楚,我真的很抱歉,因为我不是母语人士。所以尽管@rintaro回答了类似的问题,但他的答案并没有解决我的问题。 @ martin-r提出了一个Objective-C答案,它再次解决了我的问题。有另一个用户埃里克的东西,他们也提出了另一个答案,但事后删除。我只是无法理解为什么有几个人提出了不回答我的问题的不同答案。
答案 0 :(得分:7)
尝试:
let str = "someSentenceWith UTF text İŞğĞ. anotherSentenceğüÜğ"
var result = ""
str.uppercaseString.enumerateSubstringsInRange(indices(str), options: .BySentences) { (sub, _, _, _) in
result += sub[sub.startIndex ... sub.startIndex]
result += sub[sub.startIndex.successor() ..< sub.endIndex].lowercaseString
}
println(result) // -> "Somesentencewith utf text i̇şğğ. Anothersentenceğüüğ"
ADDED:Swift2
let str = "someSentenceWith UTF text İŞğĞ. anotherSentenceğüÜğ"
var result = ""
str.uppercaseString.enumerateSubstringsInRange(str.characters.indices, options: .BySentences) { (sub, _, _, _) in
result += String(sub!.characters.prefix(1))
result += String(sub!.characters.dropFirst(1)).lowercaseString
}
print(result)
答案 1 :(得分:2)
更新@ rintaro的Swift 3代码:
let str = "someSentenceWith UTF text İŞğĞ. anotherSentenceğüÜğ"
var result = ""
str.uppercased().enumerateSubstrings(in: str.startIndex..<str.endIndex, options: .bySentences) { (sub, _, _, _) in
result += String(sub!.characters.prefix(1))
result += String(sub!.characters.dropFirst(1)).lowercased()
}
print(result)
答案 2 :(得分:1)
您可以使用正则表达式来实现此目的。我将此函数添加为字符串扩展名,因此将来调用将是微不足道的:
extension String {
func toUppercaseAtSentenceBoundary() -> String {
var string = self.lowercaseString
var capacity = string.utf16Count
var mutable = NSMutableString(capacity: capacity)
mutable.appendString(string)
var error: NSError?
if let regex = NSRegularExpression(
pattern: "(?:^|\\b\\.[ ]*)(\\p{Ll})",
options: NSRegularExpressionOptions.AnchorsMatchLines,
error: &error
) {
if let results = regex.matchesInString(
string,
options: NSMatchingOptions.allZeros,
range: NSMakeRange(0, capacity)
) as? [NSTextCheckingResult] {
for result in results {
let numRanges = result.numberOfRanges
if numRanges >= 1 {
for i in 1..<numRanges {
let range = result.rangeAtIndex(i)
let substring = mutable.substringWithRange(range)
mutable.replaceCharactersInRange(range, withString: substring.uppercaseString)
}
}
}
}
}
return mutable
}
}
var string = "someSentenceWith UTF text İŞğĞ. anotherSentenceğüÜğ.".toUppercaseAtSentenceBoundary()
答案 3 :(得分:1)
我根据@ Katy的代码
在Swift 3中写了这个扩展名extension String {
func toUppercaseAtSentenceBoundary() -> String {
var result = ""
self.uppercased().enumerateSubstrings(in: self.startIndex..<self.endIndex, options: .bySentences) { (sub, _, _, _) in
result += String(sub!.characters.prefix(1))
result += String(sub!.characters.dropFirst(1)).lowercased()
}
return result as String
}
}
使用方法:
let string = "This is First sentence. This is second Sentence.".toUppercaseAtSentenceBoundary()
print(string) /* Output: "This is first sentence. This is second sentence." */