Question

我正在尝试向我的Qt应用程序添加多个线程，但是当它执行此线程时程序崩溃并且我得到错误

QThread：在线程仍在运行时被销毁

QMutex：销毁锁定的互斥锁

我理解错误消息我不知道如何解决它。我的代码如下。

标题

class Worker : public QObject
{
    Q_OBJECT
private slots:
    void onTimeout()
    {
        qDebug()<<"Worker::onTimeout get called from?: "<<QThread::currentThreadId();
    }
};

class Thread : public QThread
{
    Q_OBJECT

private:
    void run()
    {
        qDebug()<<"From work thread: "<<currentThreadId();
        QTimer timer;
        Worker worker;
        connect(&timer, SIGNAL(timeout()), &worker, SLOT(onTimeout()));
        timer.start(1000);
        exec();
    }
};

login.cpp

    void Login::on_pushButton_clicked()
{
    QSqlQuery query;
    QString Username = ui->Username_lineEdit->text();
    QString Password = ui->Password_lineEdit->text();
    query.prepare("SELECT * FROM Program_account WHERE Login = '"+ Username +"' AND Password = '"+ Password +"'");
    if(!query.exec())
    {
        qDebug() << "SQL QUERY Login:" << query.executedQuery();
        qDebug() << "SQL ERROR Login:" << query.lastError();
    }
    else if(!query.first())
    {
        tries++;
        int x = 10 - tries;
        ui->label->setText("Incorrect Username or Password " + QString::number(x) + " tries until timeout");
    }
    else
    {
        QSqlQuery Account_Type_Query("SELECT Account_Type FROM Program_account WHERE Login = '"+ Username +"' AND Password = '"+ Password +"'");
        while(Account_Type_Query.next())
        {
            Account_Type = Account_Type_Query.value(0).toInt();
        }
        tries = 0;
        static Home *home = new Home;
        home->show();
        close();
    }
    if(tries == 10)
    {
        Thread t;
        t.start();
        ui->label->setText("Password entered wrong too many times, entered 10 minute cooldown period");
        ui->pushButton->hide();
        QTimer::singleShot(600000, ui->pushButton, SLOT(show()));
        tries = 0;
        ui->label->setText("");
    }

我可以解决此问题的正确方法是什么。非常感谢所有帮助。

谢谢

更新：试着 class Thread：public QThread { Q_OBJECT

private:
    void run()
    {
        while(QThread::wait())
        {
        qDebug()<<"From work thread: "<<currentThreadId();
        QTimer timer;
        Worker worker;
        connect(&timer, SIGNAL(timeout()), &worker, SLOT(onTimeout()));
        timer.start(1000);
        exec();
        }
        QThread::quit();
    }
};

但仍然收到相同的错误

Answer 1

继承QThread是一个问题，我怀疑Worker对象没有你认为它具有的线程关联，并且正在主线程上运行。

崩溃的原因是你在堆栈上创建了Thread实例，

if(tries == 10)
{
    Thread t; // NOTE THIS IS ON THE STACK
    t.start();
    ui->label->setText("Password entered wrong too many times, entered 10 minute cooldown period");
    ui->pushButton->hide();
    QTimer::singleShot(600000, ui->pushButton, SLOT(show()));
    tries = 0;
    ui->label->setText("");
}

当Thread实例超出范围时，它将被销毁。

无论如何，我强烈建议遵循@Thomas的建议，并坚持Maya使用线程的方式，而不需要继承QThread。

QThread：线程仍在运行时销毁，QMutex被破坏

1 个答案: