Question

我有以下情况我有一个输入文件：

start-I/p      end-I/p          code 
10.35.210.1    10.35.210.255    User1
10.35.145.1    10.35.145.255    User2

我想以下列格式生成ip地址表

ip             code 
10.35.210.1    user1
10.35.210.2    user1 
10.35.210.3    user1 
10.35.210.4    user1 
...
10.35.210.255  user1

10.35.145.1    user2
10.35.145.2    user2
10.35.145.3    user2 
10.35.145.4    user2 
...
10.35.145.255  user2

任何人都可以帮我找到合适的解决方案吗？

Answer 1

以下是您的解决方案，使用sed和seq作为依赖关系，请在使用之前尝试理解代码。

#!/bin/bash
echo "ip    code";
while read start end code
do
    if [[ $start != "start-I/p" ]]
    then
        startNum=0;
        for i in $(echo $start| sed "s/\./ /g")
        do 
            #echo $i;
            (( startNum *= 256 ));
            (( startNum += $i ));       
        done

        endNum=0;
        for i in $(echo $end| sed "s/\./ /g")
        do 
            #echo $i;
            (( endNum *= 256 ));
            (( endNum += $i ));
        done

        for j in $(seq $startNum $endNum)
        do
            (( p1 = $j % 256 ));
            (( j /= 256 ));
            (( p2 = $j % 256 ));
            (( j /= 256 ));
            (( p3 = $j % 256 ));
            (( j /= 256 ));
            (( p4 = $j % 256 ));
            echo "$p4.$p3.$p2.$p1   $code";
        done
        #echo $num1;
    fi
done < $1

Shell脚本生成ip地址

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