Question

我想更新col并根据批次向列中添加5分钟。

让我们说当前快照：

Time                      | batch
2015-03-26 08:20:54.077   | 1
2015-03-26 08:20:54.077   | 1 
2015-03-26 08:20:54.077   | 1
2015-03-26 08:20:54.077   | 1
2015-03-26 08:20:54.077   | 1
2015-03-26 08:22:54.077   | 2
2015-03-26 08:22:54.077   | 2
2015-03-26 08:22:54.077   | 2
2015-03-26 08:22:54.077   | 2
2015-03-26 08:24:54.077   | 3
2015-03-26 08:24:54.077   | 3

更新后：

My_Time                      | batch
2015-03-26 08:25:54.077   | 1
2015-03-26 08:25:54.077   | 1 
2015-03-26 08:25:54.077   | 1
2015-03-26 08:25:54.077   | 1
2015-03-26 08:25:54.077   | 1
2015-03-26 08:30:54.077   | 2
2015-03-26 08:30:54.077   | 2
2015-03-26 08:30:54.077   | 2
2015-03-26 08:30:54.077   | 2
2015-03-26 08:35:54.077   | 3
2015-03-26 08:35:54.077   | 3

根据我当前的查询，不是achived.Plz指南。

UPDATE table_name SET My_Time = DATEADD(minute, 5, My_Time);

它是根据当前的延迟时间增加时间，但如何在前一批次的基础上更新？

Answer 1

试试这个

示例数据

DROP TABLE snapshot 
CREATE TABLE snapshot (time DATETIME,batchid INT)

INSERT INTO snapshot VALUES('2015-03-26 08:20:54.077', 1),
('2015-03-26 08:20:54.077', 1 ),
('2015-03-26 08:20:54.077', 1),
('2015-03-26 08:20:54.077', 1),
('2015-03-26 08:20:54.077', 1),
('2015-03-26 08:22:54.077', 2),
('2015-03-26 08:22:54.077', 2),
('2015-03-26 08:22:54.077', 2),
('2015-03-26 08:22:54.077', 2),
('2015-03-26 08:26:54.077', 3),
('2015-03-26 08:26:54.077', 3)

SELECT * FROM snapshot;

<强>查询

DECLARE @increment_by_mins INT = 5

UPDATE snapshot
SET time = updated_time
FROM snapshot
INNER JOIN
(
    SELECT batchid, DATEADD(MINUTE, @increment_by_mins * orderedid,ISNULL(LAG(time) OVER(ORDER BY batchid),time)) updated_time
    FROM
    (
        SELECT MIN(time) time,batchid,ROW_NUMBER()OVER(ORDER BY batchid ASC) as orderedid
        FROM snapshot
        GROUP BY batchid
    )updated_snapshot
)updated_snapshot
ON updated_snapshot.batchid = snapshot.batchid


SELECT * FROM snapshot;

修改

根据你的回答，你想要做的似乎与我最初提出的相似。由于您的所有时间都是基于初始批次的最短时间，因此您只需要DENSE_RANK()和DATEADD来完成所需的工作。

DECLARE @initialtime datetime; SELECT TOP 1 @initialtime = time FROM snapshot ORDER BY batchid,time; DECLARE @minutes INT = 5 ;WITH CTE AS ( SELECT time,batchid,DENSE_RANK()OVER(ORDER BY batchid ASC) oid FROM snapshot ) UPDATE CTE SET time = DATEADD(minute,@minutes * oid ,@initialtime) SELECT * FROM snapshot

Answer 2

DECLARE @tempTable TABLE 
( 
     ID int IDENTITY(1,1), 
     batchid INT
)  
     INSERT INTO @tempTable 
     SELECT distinct batchid FROM snapshot 
     declare @CuentdateTime Datetime =null
     set   @CuentdateTime =(select top 1  time from snapshot) ;
     DECLARE @tempTablecount INT 
     DECLARE @count INT = 1 
     SELECT @tempTablecount = COUNT(*) FROM @tempTable 
     WHILE(@count<=@tempTablecount) 
     BEGIN 
         select  @CuentdateTime =   DATEADD(MINUTE, 5, @CuentdateTime); 
           UPDATE snapshot SET time = @CuentdateTime where batchid=(select batchid FROM @tempTable   where id=@count)                      
     SET @count = @count + 1 
     END

更新表中的列

2 个答案: