Question

第一个JSON：

{
    "datas":[
        {
            "id":"1",
            "name":"Name 1",
            "users":"1,3"
        },
        {
            "id":"2",
            "name":"Name 2",
            "users":"2,5"
        }
    ]
}

第二个JSON：

{
    "users":[
        {
            "id":"1",
            "name":"User 1"
        },
        {
            "id":"2"
            "name":"User 2"
        }
    ......
    ]
}

但我总是得到所有用户的列表，无论我在哪里点击（名称1或名称2）

这就是我用来获取基于id的过滤用户：

@Override
protected Boolean doInBackground(String... urls) {
    try {
        String[] strMultiUsers = strEventUsers.split(",");
        List<String> listMultiUsers = Arrays.asList(strMultiUsers);           

        HttpGet httppost = new HttpGet(urls[0]);
        HttpClient httpclient = new DefaultHttpClient();
        HttpResponse response = httpclient.execute(httppost);

        int status = response.getStatusLine().getStatusCode();

        if (status == 200) {
            HttpEntity entity = response.getEntity();
            String data = EntityUtils.toString(entity);


            JSONObject jsono = new JSONObject(data);
            JSONArray jarray = jsono.getJSONArray("users");

            for (int i = 0; i < jarray.length(); i++) {
                JSONObject object = jarray.getJSONObject(i);

                UsersList oldEventsList = new UsersList();

                oldEventsList.setId(object.getString("id"));                        
                oldEventsList.setName(object.getString("name"));

                if(listMultiUsers.contains(""))
                {

                }

                oldEventsArrayList.add(oldEventsList);
            }
            return true;
        }

我希望每当用户点击名称2时，我只需要显示两个用户（id为2和5的用户）但我仍然获得所有用户（1到5）

Answer 1

我找到了解决方案，并为其他开发人员安排了：

String strUsers = object.getString("id").toString();
Log.d("users", strUsers);

usersList.setName(object.getString("name"));

if(listMultiUsers.contains(strUsers))
 {
     usersListArrayList.add(usersList);
 }

JSON解析过滤器逗号分隔的记录

1 个答案: