我有一个类似下面的PHP文件,我尝试更改文件名并给它一个随机名称,然后使用
将其保存在服务器上 $temp = explode(".",$_FILES["fileToUpload"]["name"]);
$newfilename = rand(1,99999) . '.' .end($temp);
move_uploaded_file($_FILES["fileToUpload"]["tmp_name"], $target_file . $newfilename);
以下代码
HTML:
<form action="upload.php" method="post" enctype="multipart/form-data">
Select image to upload:
<input type="file" name="fileToUpload" id="fileToUpload">
<input type="submit" value="Upload Image" name="submit">
</form>
和upload.php
PHP
<?php
$target_dir = "uploads/";
$target_file = $target_dir . basename($_FILES["fileToUpload"]["name"]);
$uploadOk = 1;
$imageFileType = pathinfo($target_file,PATHINFO_EXTENSION);
// Check if image file is a actual image or fake image
if(isset($_POST["submit"])) {
$check = getimagesize($_FILES["fileToUpload"]["tmp_name"]);
if($check !== false) {
echo "File is an image - " . $check["mime"] . ".";
$uploadOk = 1;
} else {
echo "File is not an image.";
$uploadOk = 0;
}
}
// Check if file already exists
if (file_exists($target_file)) {
echo "Sorry, file already exists.";
$uploadOk = 0;
}
// Check file size
if ($_FILES["fileToUpload"]["size"] > 500000) {
echo "Sorry, your file is too large.";
$uploadOk = 0;
}
// Allow certain file formats
if($imageFileType != "jpg" && $imageFileType != "png" && $imageFileType != "jpeg"
&& $imageFileType != "gif" ) {
echo "Sorry, only JPG, JPEG, PNG & GIF files are allowed.";
$uploadOk = 0;
}
// Check if $uploadOk is set to 0 by an error
if ($uploadOk == 0) {
echo "Sorry, your file was not uploaded.";
// if everything is ok, try to upload file
} else {
$temp = explode(".",$_FILES["fileToUpload"]["name"]);
$newfilename = rand(1,99999) . '.' .end($temp);
move_uploaded_file($_FILES["fileToUpload"]["tmp_name"], $target_file . $newfilename);
}
?>
但是这会创建一个像test.png123472.png
这样的文件,它是原始文件名test.png
和123472.png
的组合!
能告诉我为什么会发生这种情况以及如何解决这个问题吗?
答案 0 :(得分:1)
问题出在以下一行
move_uploaded_file($_FILES["fileToUpload"]["tmp_name"], $target_file . $newfilename);
而是使用以下行
move_uploaded_file($_FILES["fileToUpload"]["tmp_name"], $target_dir. $newfilename);
从代码中删除以下行:
$target_file = $target_dir . basename($_FILES["fileToUpload"]["name"]);
答案 1 :(得分:0)
请尝试这样,
$temp = explode(".",$_FILES["fileToUpload"]["name"][0]);
$newfilename = rand(1,99999) . '.' .end($temp);