Question

在我的申请中，我需要分别得到小时和分钟：

NSString *currentHour=[string1 substringWithRange: NSMakeRange(0,2)];
        int currentHourInNumber=[currentHour intValue];

考虑string1包含来自datepicker的11:59:13 AM。

如果我使用上面的代码，如果它大于9，则可以获得小时。否则我需要更改NSMakeRange(0,1)以获得1到9之间的小时。

有没有方法可以获得小时，分钟等？

提前致谢，请提供示例代码。

Answer 1

使用NSDateFormatter将string1转换为NSDate，然后获取所需的NSDateComponents：

<强>的OBJ-C ：

NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:@"<your date format goes here"];
NSDate *date = [dateFormatter dateFromString:string1];
NSCalendar *calendar = [NSCalendar currentCalendar];
NSDateComponents *components = [calendar components:(NSCalendarUnitHour | NSCalendarUnitMinute) fromDate:date];
NSInteger hour = [components hour];
NSInteger minute = [components minute];

Swift 1和2 ：

let dateFormatter = NSDateFormatter()
dateFormatter.dateFormat = "Your date Format"
let date = dateFormatter.dateFromString(string1)
let calendar = NSCalendar.currentCalendar()
let comp = calendar.components([.Hour, .Minute], fromDate: date)
let hour = comp.hour
let minute = comp.minute

Swift 3 ：

let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "Your date Format"
let date = dateFormatter.date(from: string1)
let calendar = Calendar.current
let comp = calendar.dateComponents([.hour, .minute], from: date)
let hour = comp.hour
let minute = comp.minute

有关dateformat的更多信息，请访问官方unicode网站

Answer 2

如果您只需要它作为字符串呈现，则以下代码更容易

NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
[formatter setDateFormat:@"HH:mm"];

NSString *startTimeString = [formatter stringFromDate:startTimePicker.date];

Answer 3

在我看来，这就是问题所在，不需要格式化程序：

NSDate *date = [NSDate date];
NSCalendar *calendar = [NSCalendar currentCalendar];
NSDateComponents *components = [calendar components:(NSCalendarUnitHour | NSCalendarUnitMinute) fromDate:date];
NSInteger hour = [components hour];
NSInteger minute = [components minute];

Answer 4

NSDateComponents

您可以在这里找到所有需要：
https://developer.apple.com/library/content/documentation/Cocoa/Conceptual/DatesAndTimes/Articles/dtCalendars.html

Answer 5

如果你要使用C库，那么可以这样做：

time_t t;
struct tm * timeinfo;

time (&t);
timeinfo = localtime (&t);

NSLog(@"Hour: %d Minutes: %d", timeinfo->tm_hour, timeinfo->tm_min);

使用Swift：

var t = time_t()
time(&t)
let x = localtime(&t)

println("Hour: \(x.memory.tm_hour) Minutes: \(x.memory.tm_min)")

如需进一步指导，请参阅：http://www.cplusplus.com/reference/ctime/localtime/

Answer 6

在iOS 8中，Apple推出了一种帮助方法，用于从NSDate对象中检索hour，minute，second和nanosecond。

目标-C

NSDate *date = [NSDate currentDate];
NSInteger hour = 0;
NSInteger minute = 0;
NSCalendar *currentCalendar = [NSCalendar currentCalendar];
[currentCalendar getHour:&hour minute:&minute second:NULL nanosecond:NULL fromDate:date];
NSLog(@"the hour is %ld and minute is %ld", (long)hour, (long)minute);

夫特

let date = NSDate()
var hour = 0
var minute = 0
let calendar = NSCalendar.currentCalendar()
if #available(iOS 8.0, *) {
    calendar.getHour(&hour, minute: &minute, second: nil, nanosecond: nil, fromDate: date)
    print("the hour is \(hour) and minute is \(minute)")
}

Answer 7

Swift 2.0

    let dateNow = NSDate()
    let calendar = NSCalendar.currentCalendar()
    let hour = calendar.component(NSCalendarUnit.Hour, fromDate: dateNow)
    let minute = calendar.component(NSCalendarUnit.Minute, fromDate: dateNow)
    print(String(hour))
    print(String(minute))

请注意print语句中对String的强制转换，您可以轻松地将该值赋给变量，如下所示：

var hoursString = String(hour)
var minutesString = String(minute)

然后你可以连接像这样的值：

var compoundString = "\(hour):\(minute)"
print(compoundString)

Answer 8

Swift 2.0

你可以做以下事情来获取日期和时间：

let dateFromat = NSDateFormatter()
dateFromat.dateFormat = "hh:mm a"
let date = dateFromat.dateFromString(string1) // In your case its string1
print(date) // you will get - 11:59 AM

我如何从NSDate获得小时和分钟？

8 个答案: