Question

程序必须循环，读入数据，计算每个员工的值，并将结果输出到文本文件。

问题是我的代码中的while循环是无限循环的，我不知道如何让它停止（在下一行不是我们正在寻找的那一点）。编译器没有发现错误，我无法在互联网上的其他地方找到可行的答案。

inFile >> employee_number >> hourly_rate >> hours_worked >> dependents >> full_time;

while (employee_number == 1)
{
    count++;

    PayrollMath(hours_worked, hourly_rate, base_pay, gross_pay, overtime_hours, overtime_pay, double_overtime_hours, double_overtime_pay);

    IRA_Deduction = RetirementSavings(gross_pay);
    mod_gross_pay = gross_pay - IRA_Deduction;

    taxes_withheld = IncomeTaxWithholding(dependents, mod_gross_pay);
    net_pay = mod_gross_pay - taxes_withheld;

    MedicalDeductions(net_pay, full_time, medical_benefits);

    number_of_employed = count;

    ProgramOutput(number_of_employed, hours_worked, hourly_rate, base_pay, overtime_hours, overtime_pay, double_overtime_hours,
                  double_overtime_pay, gross_pay, IRA_Deduction, mod_gross_pay, taxes_withheld, net_pay, medical_benefits);

}

cout << " Successful Completion!" << endl;

outFile.close();
inFile.close();

Answer 1

这是代码的简化版本，仅包含对循环行为有用的内容：

inFile >> employee_number >> hourly_rate >> hours_worked >> dependents >> full_time;

while (employee_number == 1)
{
    count++;
    number_of_employed = count;
}

outFile.close();
inFile.close();

在循环中，您反复检查条件是否更改为一个值，该值指示应该断开循环的时间。问题是您的条件是常量，因为在每个循环迭代期间不会修改条件中使用的变量。条件反复评估相同的值，永远不会通过改变条件给循环一个破解的机会。

while(employee_number == 1){...} // employee_number is untouched

while(true){...} // equivalent, as condition never changes (is constant)

要在某个时刻进行循环中断，您需要修改循环内条件中使用的变量。

while(employee_number == 1){... /* modifying emloyee_number */ ...}

如果我们假设您想要读取每一行，直到下一行将employee_number读为0，那么我认为您应该使用它：

while (true)
{
    inFile >> employee_number >> hourly_rate >> hours_worked >> dependents >> full_time;
    if (employee_number == 0) break;

    number_of_employed++;

    // Do your things with the line readings
}

while循环的文件I / O问题

1 个答案: