Question

我想使用下一个数组创建一个树：

int numbers[] = {4,6,7,23,60};

这个想法是数字总和为100。

我想使用下一种格式在树中订购此列表：

1.如果treeLeafNode空间不存在，请创建它。

取最低值（4,6 ......此值将是子节点）并进行求和。（10 ...这将是父节点）

3.使用父节点修改列表，现在有（10,7,23,60）

从您现在的低数字排序（7,10,23,60）

重新执行步骤1,2,3,4，直至到达顶部＆＃39;，即（LeftChildNode：40，ParentNode：100，RightChildNode：60）;

< / LI>

问题：从现在的工具中，创建树的最简单方法是什么？

这是我到目前为止所做的事情。

我有这个功能：修剪，从低到高排序。问题：我的树创建功能如下......但是达到了分段错误：

void insert_Leaf(int L,int R, hojaNodo **leaf)
{

//JiCase 
    if(L+R >= 101)
        return;



    hojaNodo *tempLeafMain;
    tempLeafMain = (hojaNodo*)malloc(sizeof(hojaNodo));
    tempLeafMain = *leaf;

    hojaNodo *tempLeafLeft;
    tempLeafLeft = (hojaNodo*)malloc(sizeof(hojaNodo));




    int tempLeft = L;
    int tempRight = R;
    int tempParent = tempLeft + tempRight;
    //Creamos Parent
  if(tempLeafMain == 0)
    {


    hojaNodo *tempLeafRight;
    tempLeafRight = (hojaNodo*)malloc(sizeof(hojaNodo));


      tempLeafMain->probabilidad = tempParent;
      // init los hijos a null 
      tempLeafMain->left = tempLeafLeft;
      tempLeafMain->right = tempLeafRight;

      tempLeafLeft ->probabilidad = tempLeft;
      tempLeafRight->probabilidad = tempRight;

      return;
    }//eof check doesnt exist

   else if(tempLeafMain != NULL){
   if(tempLeft < tempLeafMain->probabilidad){

    hojaNodo *tempLeafParent;
    tempLeafParent = (hojaNodo*)malloc(sizeof(hojaNodo));
    tempLeafParent->probabilidad = tempLeft + tempLeafMain->probabilidad;
    tempLeafParent->right = tempLeafMain;
    tempLeafParent->left = tempLeafLeft;

    tempLeafLeft->probabilidad = tempLeft;
    //tempLeaf->right = *leaf;
    *leaf = tempLeafParent;
    }//eof if

   }//elseif

   }//eof insertLeaf

感谢您的时间，如果可能的话，感谢您的帮助。祝你有个美好的一天！

Answer 1

这是解决分段错误后代码的样子。

void insert_Leaf(int L,int R, hojaNodo **leaf)
{

//JiCase
printf("inside insert_leaf\n");

    if(L+R >= 101)
        return;


    hojaNodo *tempLeafHead;
    tempLeafHead = (hojaNodo*)malloc(sizeof(hojaNodo));
    tempLeafHead = *leaf;





    int tempLeft = L;
    int tempRight = R;
    int tempParent = tempLeft + tempRight;
    //Creamos Parent
  if(tempLeafHead == 0)
    {
    printf("head is null\n");


    tempLeafHead = (hojaNodo*)malloc(sizeof(hojaNodo));

    hojaNodo *tempLeafLeftChild;
    tempLeafLeftChild = (hojaNodo*)malloc(sizeof(hojaNodo));

    hojaNodo *tempLeafRightChild;
    tempLeafRightChild = (hojaNodo*)malloc(sizeof(hojaNodo));


      tempLeafHead->probabilidad = tempLeft + tempRight;
      tempLeafHead->left = tempLeafLeftChild;
      tempLeafHead->right = tempLeafRightChild;
      tempLeafLeftChild->probabilidad = tempLeft;
      tempLeafRightChild->probabilidad = tempRight;
      *leaf = tempLeafHead;
      return;
    } else if(tempLeafHead != NULL){

    printf("head is NOT null\n");
        if(tempLeft < tempLeafHead->probabilidad){

        hojaNodo *tempLeafParent;
        tempLeafParent = (hojaNodo*)malloc(sizeof(hojaNodo));

        hojaNodo *tempLeafLeftChild;
        tempLeafLeftChild = (hojaNodo*)malloc(sizeof(hojaNodo));

        tempLeafParent->probabilidad = tempLeft + tempLeafHead->probabilidad;
        tempLeafParent->right = tempLeafHead;
        tempLeafParent->left = tempLeafLeftChild;

        tempLeafLeftChild->probabilidad = tempLeft;
        //tempLeaf->right = *leaf;
        *leaf = tempLeafParent;
        }//eof if

   }//elseif

}//eof insertLeaf

对二叉树进行排序 - 函数到达seg。故障

1 个答案: