jQuery如何在原型中调用方法?

时间:2015-03-25 18:42:10

标签: javascript jquery

jQuery的:

    function Morphing( button, container, content) {
    this.button = button;
    this.container = container;
    this.content = content;
    this.overlay = $('div.overlay');
}

Morphing.prototype.startMorph = function() {
    this.button.on('click', function() {
        $(this).fadeOut(200);
        Morphing.containerMove();
        // Work on from here!
        // setTimeout(Morphing.containerMove, 200);
    });
};

Morphing.prototype.containerMove = function() {
    console.log(this);
    this.overlay.fadeIn();
    this.container.addClass('active');

    this.container.animate(Morphing.endPosition, 400, function() {
            this.content.fadeIn();
            this.span.fadeIn();
            Morphing.close();
    });
};

我试图在单击按钮时运行containerMove函数,但我收到错误:

[Error] TypeError: undefined is not a function (evaluating 'Morphing.containerMove()')
    (anonymous function) (newScript.js, line 11)
    dispatch (jquery.min.js, line 3)
    i (jquery.min.js, line 3)

这是唯一的错误。我认为这是因为我不正确地调用该方法?感谢。

旁注:在原型中编写方法就像我做了一个好习惯一样吗?

额外代码:

忘记提及,这是在我的index.html:

<script>
$(document).ready(function() {

    var morph = new Morphing( $('button.morphButton'), $('div.morphContainer'), $('h1.content, p.content') );

    morph.startMorph();

});

</script>

1 个答案:

答案 0 :(得分:3)

最简单的方法是将原始this存储在闭包

Morphing.prototype.startMorph = function() {
    var me = this;
    this.button.on('click', function() {
        $(this).fadeOut(200);
        me.containerMove();
        // Now for the set timeout, you'll want to make sure it's
        // called with the corect `this`, You can use Function.bind
        // See https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Function/bind
        setTimeout(me.containerMove.bind(me), 200);
    });
};

在您的事件处理程序中,this指向元素本身,因为您似乎从您调用$(this).fadeOut(200);但您需要访问处理程序之外的this这一事实中理解