结合两个ajax调用 - 在url中存储多个post变量

时间：2015-03-25 15:21:44

标签： php jquery html mysql ajax

我想结合这两个ajax调用，我希望能够将两个post变量存储在url中，因为它只能在其中一个存储在特定时间：

 <script>
            function showUser() {
                var selectedPerson = $('#testform').serialize();
                                                    document.getElementById("txtHint").innerHTML = "<div class='loading-indication'><img src='ajax-loader.gif' /> &nbsp; Please wait... Loading New Courses...</div>";


                $.ajax({
                    url:'getuser.php',
                    type:'post',
                    data:selectedPerson,
                    success:function(res){
                        $('#txtHint').html(res);
                    }
                })
            }
        </script>

        <script>
            function showUser2() {
                var selectedPerson = $('#testform2').serialize();
                                                    document.getElementById("txtHint").innerHTML = "<div class='loading-indication'><img src='ajax-loader.gif' /> &nbsp; Please wait... Loading New Courses...</div>";


                $.ajax({
                    url:'getuser.php',
                    type:'post',
                    data:selectedPerson,
                    success:function(res){
                        $('#txtHint').html(res);
                    }
                })
            }
        </script>

以下是php部分：

$person  = isset($_POST['person']) ? $_POST['person'] : '';
$allIds = '';
if($person!='')
{
    $allIds = implode(',', $person);
}


$person2  = isset($_POST['person2']) ? $_POST['person2'] : '';
$allIds2 = '';
if($person2!='')
{
    $allIds2 = implode(',', $person2);
}

如果需要澄清，请告诉我

更新

<html>
    <head>
        <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.2/jquery.min.js"></script>
        <script>
            function showUser() {
                var selectedPerson = $('#testform').serialize();
                                                    document.getElementById("txtHint").innerHTML = "<div class='loading-indication'><img src='ajax-loader.gif' /> &nbsp; Please wait... Loading New Courses...</div>";


                $.ajax({
                    url:'getuser.php',
                    type:'post',
                    data:selectedPerson,
                    success:function(res){
                        $('#txtHint').html(res);
                    }
                })
            }
        </script>

        <script>
            function showUser2() {
                var selectedPerson = $('#testform2').serialize();
                                                    document.getElementById("txtHint").innerHTML = "<div class='loading-indication'><img src='ajax-loader.gif' /> &nbsp; Please wait... Loading New Courses...</div>";


                $.ajax({
                    url:'getuser.php',
                    type:'post',
                    data:selectedPerson,
                    success:function(res){
                        $('#txtHint').html(res);
                    }
                })
            }
        </script>
    </head>
    <body>

        <form id="testform">
            <input onchange="showUser();" name="person[]" type="checkbox" value="1">One<br>
                        <input onchange="showUser();" name="person[]" type="checkbox" value="2">Two<br>
                                                <input onchange="showUser();" name="person[]" type="checkbox" value="3">Three<br>



        </form>

        <br>
        <div id="txtHint"><b>Person info will be listed here...</b></div>

    </body>
</html>

更新

PHP整个代码

<!DOCTYPE html>
<html>
<head>

</head>
<body>

<?php
$person  = isset($_POST['person']) ? $_POST['person'] : '';
$allIds = '';
if($person!='')
{
    $allIds = implode(',', $person);
}


$person2  = isset($_POST['person2']) ? $_POST['person2'] : '';
$allIds2 = '';
if($person2!='')
{
    $allIds2 = implode(',', $person2);
}





include("includes/db.php"); 



global $con;


$sql= "SELECT * FROM courses WHERE (course_duration IN ('" . $allIds . "')) LIMIT 10";
$result = mysqli_query($con,$sql);
$sqlCount = "SELECT * FROM courses WHERE (course_duration IN ('" . $allIds . "'))";
$get_crs_count = mysqli_query($con, $sqlCount);
$count_rows = mysqli_num_rows($get_crs_count);
echo '<p style="margin-bottom: 8px;margin-top: 8px;font-size:18px;"><b>Number of courses available: </b>' . $count_rows ;
while($row_crs = mysqli_fetch_array($result)){ 

    $crs_id = $row_crs['course_id'];
        $crs_cat = $row_crs['course_cat'];

    $crs_provider = $row_crs['course_provider'];

    $crs_title = $row_crs['course_title'];
        $crs_price = $row_crs['course_price'];
          $crs_city= $row_crs['course_city'];
                      $crs_category= $row_crs['course_cat1'];

          $crs_date= $row_crs['course_date1'];


$crs_sdesc= $row_crs['course_sdesc'];
$crs_shortdesc = mb_strimwidth("$crs_sdesc",0,140,"...");
        $crs_image = $row_crs['course_image'];
        $provider_image = $row_crs['provider_image'];


  echo " <article class='search-result row'><center>
      <div class='col-xs-12 col-sm-12 col-md-3' id='thumbnailContainer'>
        <a href='#' title='Lorem ipsum' class='thumbnail' id='resultThumbnail'><img src='$provider_image' /></a>
     <a href='searchPage.php?crs_price=$crs_price' style='color:black;'>  <button id='resultprice'><span id='resultpriceText'>$ $crs_price</span></button></a>
      </div>
      <div class='col-xs-12 col-sm-12 col-md-2'>
        <ul class='meta-search' id='listDesign'>
        <a href='searchPage.php?crs_date=$crs_date' style='color:white;'>   <li><button id='resultInfo'><i class='fa fa-calendar fa-1x'><span id='iconText'>  $crs_date</span></i></button></li></a>
         <a href='searchPage.php?crs_category=$crs_category' style='color:white;'>   <li><button id='resultInfo2'><i class='fa fa fa-tags fa-1x'><span id='iconText'> $crs_category</span></i></button></li></a>
<a href='searchPage.php?crs_provider=$crs_provider' style='color:white;'><li><button id='resultInfo'><i class='fa fa-graduation-cap fa-1x'><span id='iconText'>  $crs_provider</span></i></button></li></a>
<a href='searchPage.php?city=$crs_city' style='color:white;'><li><button id='resultInfo'><i class='fa fa-map-marker fa-1x'><span id='iconText'> $crs_city</span></i></button></li></a>
        </ul>
      </div></center>
      <div class='col-xs-12 col-sm-12 col-md-7 excerpet'>
        <h3 id='resultHeading'><a href='coursePage.php?crs_id=$crs_id' id='headingLinking'><b>$crs_title</b></a></h3>

        <div id='courseshortDescription'>
$crs_shortdesc
 <center><a href='coursePage.php?crs_id=$crs_id' style='color:white;'><button class='btn btn-danger' id='findoutBtn'>Find Out More</button></a> </center>
        </div>  

</div>

      <span class='clearfix borda'></span>
    </article>";
}

mysqli_close($con);
?>
</body>
</html>

课程： enter image description here

1 个答案:

答案 0 :(得分：1)

实际上serialize()可以接受这两种形式：

        function showUser() {
            var datastring = $('#testform, #testform2').serialize();
            document.getElementById("txtHint").innerHTML = "<div class='loading-indication'><img src='ajax-loader.gif' /> &nbsp; Please wait... Loading New Courses...</div>";

            $.ajax({
                url: 'getuser.php',
                type: 'post',
                data: datastring,
                success: function (res) {
                    $('#txtHint').html(res);
                }
            })
        }
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