我有3个txt文件s1.txt, s2.txt, s3.txt
。每个文件都有相同的格式和数量。我想只将3个文件中每个文件的第二列合并为一个文件。在我合并数据之前,我按照第1栏对其进行了分类:
UnSorted文件: s1.txt s2.txt s3.txt
1 23 2 33 3 22
4 32 4 32 2 11
5 22 1 10 5 28
2 55 8 11 7 11
排序文件: s1.txt s2.txt s3.txt
1 23 1 10 2 11
2 55 2 33 3 22
4 32 4 32 5 28
5 22 8 11 7 11
这是我到目前为止的代码:
BaseFile ='s'
n=3
fid=fopen('RT.txt','w');
for i=1:n
%Open each file consecutively
d(i)=fopen([BaseFile num2str(i)'.txt']);
%read data from file
A=textscan(d(i),'%f%f')
a=A{1}
b=A{2}
ab=[a,b];
%sort the data according to the 1st column
B=sortrows(ab,1);
%delete the 1st column after being sorted
B(:,1)=[]
%write to a new file
fprintf(fid,'%d\n',B');
%close (d(i));
end
fclose(fid);
如何以这种格式获取新txt文件中的输出?
23 10 11
55 33 22
32 32 28
22 11 11
而不是这种格式?
23
55
32
22
10
33
32
11
11
22
28
11
答案 0 :(得分:10)
首先创建输出矩阵,然后将其写入文件。
这是新代码:
BaseFile ='s';
n=3;
for i=1:n % it's not recommended to use i or j as variables, since they used in complex math, but I'll leave it up to you
% Open each file consecutively
d=fopen([BaseFile num2str(i) '.txt']);
% read data from file
A=textscan(d,'%f%f', 'CollectOutput',1);
% sort the data according to the 1st column
B=sortrows(A{:},1);
% Instead of deleting a column create new matrix
if(i==1)
C = zeros(size(B,1),n);
end
% Check input file and save the 2nd column
if size(B,1) ~= size(C,1)
error('Input files have different number of rows');
end
C(:,i) = B(:,2);
% don't write yet
fclose (d);
end
% write to a new file
fid=fopen('RT.txt','w');
for k=1:size(C,1)
fprintf(fid, [repmat('%d\t',1,n-1) '%d\n'], C(k,:));
end
fclose(fid);
修改强> 实际上只将数字写入一个不需要FPRINTF的文件。请改用DLMWRITE:
dlmwrite('RT.txt',C,'\t')