Question

下面的代码是一个想要使用枚举器与远程服务器通信的actor的简单示例。应该可以将新数据推送到枚举器。但是，我不知道该怎么做。我在this问题中找到了一个解决方案，但Enumerator.imperative已被弃用并且根据Play！ docs似乎被Concurrent.unicast取代，它没有push方法。

// WorkerActor
val stdin = Concurrent.unicast[Array[Byte]](onStart = channel => {
  channel.push("uname -a\n".toCharArray.map(_.toByte)) // First message
}) >>> Enumerator.eof

attachStream(stdin)

def receive = LoggingReceive {
  case message: Array[Byte] =>
    // TODO: push the message to the stream
    // stdin push message ?
    ...
}

感谢您提供任何帮助。

Answer 1

您需要捕获频道，例如，您可以在演员内部执行此操作：

// WorkerActor
case class GotChannel(channel: Channel[Array[Byte]])
case object ChannelClosed
case class ChannelError(msg: String)
val stdin = Concurrent.unicast[Array[Byte]](
  // you cannot change actor state from in here, it is on another thread
  onStart = channel => self ! GotChannel(channel),
  onComplete = () => self ! ChannelClosed,
  onError = (msg, _) => self ! ChannelError(msg)
) >>> Enumerator.eof

attachStream(stdin)

def receive = {
  case GotChannel(channel) =>
    channel.push("uname -a\n".toCharArray.map(_.toByte))
    context.become(active(channel))
}

def active(channel: Channel[Array[Byte]]): Actor.Receive = LoggingReceive {
  case message: Array[Byte] =>
    // push the message to the stream
    channel.push(message)
    ...
  // handle ChannelClosed and ChannelError here
}

如何将数据推送到枚举器

1 个答案: