Question

在模型中，我有以下逻辑：

$criteria = new CDbCriteria();
$criteria->select = 'COALESCE(oca.reason, ocd.reason) AS reward_name, SUM(t.points) AS points, COUNT(t.redeemed_code_id) AS totalCount';
$criteria->join = 'LEFT JOIN organisation_classroom_deductions ocd ON ocd.deduction_id = t.order_product_id AND t.type = 1
                   LEFT JOIN organisation_classroom_achievements oca ON oca.achievement_id = t.order_product_id AND t.type = 2
                   LEFT JOIN myuser ON (myuser.user_id = t.myuser_id)';
$criteria->condition = 'myuser.organisation_id ='. user()->data->organisation->organisation_id;
$criteria->group = 't.order_product_id, t.type';

这有以下SQL查询 -

SELECT COALESCE (oca.reason, ocd.reason) AS reward, SUM(t.points) AS points, COUNT(t.redeemed_code_id) AS totalCount
FROM
`organisation_classroom_redeemed_codes` `t`
  LEFT JOIN organisation_classroom_deductions ocd ON ocd.deduction_id = t.order_product_i AND t.type = 1 LEFT JOIN organisation_classroom_achievements oca ON oca.achievement_id = t.order_product_id AND t.type = 2 LEFT JOIN myuser ON (myuser.user_id = t.myuser_id)
  WHERE myuser.organisation_id = 37383
  GROUP BY t.order_product_id, t.type

直接在数据库中运行时，此查询正常工作并返回预期的数据。但是问题是当我将条件逻辑运行到我的CAtiveDataProvider（）中时，我得到了错误。

    return new CActiveDataProvider($this, array(
        'criteria' => $criteria
    ));

有人可以建议如何解决这个问题，让它与我的CActiveDataProvider一起工作吗？

Answer 1

按如下方式指定您的选择：

$criteria->select = array(
    'COALESCE(oca.reason, ocd.reason) AS reward_name',
    'SUM(t.points) AS points',
    'COUNT(t.redeemed_code_id) AS totalCount'
);

您的代码失败的原因是CActiveFinder的第917行（至少在我使用的Yii 1.14中）使用以下逻辑来处理字符串select语句：

if(is_string($select))
    $select=explode(',',$select);

由于你在表达式中有逗号，所以爆炸在你的select语句中失败了。如上所示，将select格式化为数组，以避免此问题。

列错误无效 - 必须存在于表中或是带别名的表达式（Yii 1.x）

1 个答案: